3 years ago

An orange of mass m falls into a wagon. Assume the orange experiences upward acceleration magnitude a

Physics

1 answer:

hammer [34]3 years ago

8 0

Answer:f^n=m(a+g)

Explanation:khan academy said

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What is the avarage velocity of a car that travels 30 kilometers due west in 0.5 hours

Fed [463]

Velocity is distance over time $v= \frac{d}{t}$ . If it wants it in km/h you're good to go otherwise if its m/s you need to convert km to m by multiplying 30 by 1000 and t in hours to seconds by multiplying 0.5 by 3600.

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3 years ago

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Emily uses a rifle to shoot a bullet at a target. The bullet has a mass of 13 grams. The rifle has a mass of 3,500 grams. When s

sp2606 [1]

Force exerted by the bullet = mass * acceleration = 0.013 * 850 = 11.05 Newtons.

the rifle exerts same force in opposite direction so we have

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3 years ago

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At the top of a looped section of roller coaster track, the car and rider are completely upside down. Engineers calculated that

Pie

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m v^2 / R = m g where gravitational force provides centripetal force

R = v^2 / g = 14.3^2 m/s / 9.8 m/s^2 = 20.9 m

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3 years ago

After crossing the finish line, a race car slows down from 47 m/s to 32m/s in 3seconds. What is the car’s acceleration?

Lisa [10]

Answer: -5 m/s^2

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3 years ago

A solid sphere with a radius of 50.0 cm has a total positive charge of 40.0 μC uniformly distributed in its volume. Calculate th

il63 [147K]

Answer:

$E=2.88\times 10^5\ N/C$

Explanation:

It is given that,

The radius of the solid sphere, R = 50 cm = 0.5 m

Charge on the sphere, $q=40\ \mu C=40\times 10^{-6}\ C$

We need to find the magnitude of the electric field r = 10.0 cm away from the center of the sphere. The electric field at point r away form the center of the sphere is given by :

$E=\dfrac{kqr}{R^3}$

$E=\dfrac{9\times 10^9\times 40\times 10^{-6}\times 0.1}{0.5^3}$

$E=2.88\times 10^5\ N/C$

So, the electric field 10.0 cm away from the center of the sphere is $2.88\times 10^5\ N/C$ . Hence, this is the required solution.

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3 years ago