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mixer [17]
3 years ago
15

Where are the parallelograms in this picture?

Mathematics
1 answer:
inysia [295]3 years ago
7 0

Answer:

here the line A and H are parallel

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(2x^3-5x^2+8)(x+3)=?
Alla [95]
(2x³ - 5x² + 8)(x + 3) = ?
First step is to distribute.

2x^4 + 6x³ - 5x³ - 15x² + 8x + 24
Now combine like terms.

2x^4 + x³ - 15x² + 8x + 24

This is your answer, since you can't simplify any further or solve it without some more information.
8 0
3 years ago
Which way shows one way you can decompose 15 to find 42 x 15?
soldier1979 [14.2K]

Answer:

42 * 10 + 42 * 5

which agrees with the third option (C) shown on the list of possible answers

Step-by-step explanation:

Notice that using distributive property we can write:

42 * 15 = 42 (10 + 5) = 42 * 10 + 42 * 5

which agrees with the third option (C) shown on the list of possible answers.

5 0
2 years ago
Compare the line passing through the points (–2, –9) and (4, 6) to the line given by the equation y = 25x – 4.
elena-s [515]

Answer:

D. They have the same y-intercep

Step-by-step explanation:

Before the comparison will be efficient, let's determine the equation of the two points and the x intercept .

(–2, –9) and (4, 6)

Gradient= (6--9)/(4--2)

Gradient= (6+9)/(4+2)

Gradient= 15/6

Gradient= 5/2

Choosing (–2, –9)

The equation of the line

(Y+9)= 5/2(x+2)

2(y+9)= 5(x+2)

2y +18 = 5x +10

2y =5x -8

Y= 5/2x -4

Choosing (4, 6)

The equation of line

(Y-6)= 5/2(x-4)

2(y-6) = 5(x-4)

2y -12 = 5x -20

2y = 5x-8

Y= 5/2x -4

From the above solution it's clear that the only thing the both equation have in common to the given equation is -4 which is the y intercept

4 0
3 years ago
If f(x) -V7-3, complete the following statement (round your answer
nikklg [1K]

Answer:

- 1.67

Step-by-step explanation:

f(x) = \frac{3}{7+2} - \sqrt{7-3}

    =  \frac{3}{9} - \sqrt{4}

    = \frac{1}{3} - 2

    = - 1 \frac{2}{3}

    = -1.6666666

    = -1.67

5 0
3 years ago
Find the slope and the y-intercept of the graph of y=11+1.5x.
Anni [7]
Honestly man i don’t know Im in 6th grade bro
6 0
3 years ago
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