Answer:
The correct options are;
C. The magnitude of attraction from its nucleus
D. The distance between the electrons and its nucleus
Explanation:
The atomic radius reduces, within a given period, as we move from left to right, the number of protons increases alongside the number of electrons and the while the quantum shell to which the extra electrons are added to is the same. Therefore, the radius of the atom is dependent on the magnitude of the attraction from the nucleus
Similarly, as we progress to the next period, with an extra quantum shell, the atomic radius is seen to increase.
Therefore, the atomic radius is determined by the distance between the electrons and its nucleus.
The speed of sound depends on these two things: The type of medium and the temperature of the medium; option a.
<h3>What is the speed of sound?</h3>
The speed of sound is the distance covered in meters over a given period of time.
Speed = distance/time
The speed of sound depends on the following:
- temperature - the speed of sound increases with temperature
- medium - the speed of sound increases with increase in density of the medium.
In conclusion, the speed of sound increases with temperature.
Learn more about speed of sound at: brainly.com/question/95976
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- wet seving has ben
Explanation:
1. wet seving has been propsed as amethofolog to study aggregete stability aganist watet erosion
<span>(1) The atom absorbs energy, and one or more electrons move to a higher electron shell.</span>
Answer:
The amount of heat released is 11.3 KJ
Explanation:
H20(g) -> H20(l) + heat
This reaction is changing state from gaseous to liquid without changing the temperature. This heat is know as Latent heat. It is the energy required for a phase change.
Heat released by 5 g of water vapor (Q) = M × L
where M = mass of vapor
L= latent heat
Latent heat can be divide into 2
- Latent heat of fusion
- Latent heat of vaporization
Since we are change the gaseous state to liquid, we will be working with Latent heat of vaporization which has a value of 22.6 x 10 ∧5 J/kg
(Q) = M × L
= 0.005 x 22.6 x 10 ∧5
= 11300 J
= 11.3 KJ
