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3 years ago

6

The United Nations defines sustainable land management (SLM) as "the use of land resources, including soils, water, animals and

2 answers:

Marta_Voda [28]3 years ago

6 0

Answer:

b

Explanation:

Ede4ka [16]3 years ago

4 0

I think the answer is D.

The SLM states for long term productive potential, the other three are clear on how this would affect the future in these areas, but D pertains to the now of tilling and mulching the ground. Though it looks like all the statements are true, D doesn’t it with the UN’s SLM.

Hope this help!

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At 25 °c only 0.0260 mol of the generic salt ab3 is soluble in 1.00 l of water. what is the ksp of the salt at 25 °c?

Sladkaya [172]

Given:

At 25 degrees Celcius:

amount of generic salt AB3 = 0.0260 moles
Volume of solvent = 1.0 L water

Set up a balanced chemical equation:

AB3 =========> A3+ + 3B-
0.0260M 0.0260 0.078

Ksp = [A][B]^3
Ksp = 1.23 x 10^-5<span />

4 0

3 years ago

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Acetic acid (HC2H3O2, Ka=1.8x10^-5) is a weak acid. Calculate the pH of an aqueous solution of .25M acetic acid.

tensa zangetsu [6.8K]

Answer: The pH of an aqueous solution of .25M acetic acid is 2.7

Explanation:

$HC_2H_3O_2\rightarrow H^+C_2H_3O_2^-$

cM 0 0

$c-c\alpha$ $c\alpha$ $c\alpha$

So dissociation constant will be:

$K_a=\frac{(c\alpha)^{2}}{c-c\alpha}$

Give c= 0.25 M and $\alpha$ = ?

$K_a=1.8\times 10^{-5}$

Putting in the values we get:

$1.8\times 10^{-5}=\frac{(0.25\times \alpha)^2}{(0.25-0.25\times \alpha)}$

$(\alpha)=0.0084$

$[H^+]=c\times \alpha$

$[H^+]=0.25\times 0.0084=0.0021$

Also $pH=-log[H^+]$

$pH=-log[0.0021]=2.7$

Thus pH is 2.7

5 0

3 years ago

Determine the value of the equilibrium constant, Kgoal, for the reactionN2(g)+H2O(g)⇌NO(g)+12N2H4(g), Kgoal=?by making use of th

Black_prince [1.1K]

Answer:

$K_{goal}=1.793*10^{-33}$

Explanation:

N2(g)+O2(g)⇌2NO(g), $K_1 = 4.10*10^{-31}$

N2(g)+2H2(g)⇌N2H4(g), $K_2 = 7.40*10^{-26}$

2H2O(g)⇌2H2(g)+O2(g), $K_3 = 1.06*10^{-10}$

If we add above reaction we will get:

2N2(g)+2H2O(g)⇌2NO(g)+N2H4(g) Eq (1)

Equilibrium constant for Eq (1) is $K_1*K_3*K_3$

Divide Eq (1) by 2, it will become:

N2(g)+H2O(g)⇌NO(g)+1/2N2H4(g) Eq (2)

Equilibrium constant for Eq (2) is $(K_1*K_3*K_3)^{1/2}$

$Equilibrium constant =K_{goal}= (K_1*K_2*K_3)^{1/2}\\K_{goal}= (4.10*10^{-31} *7.40*10^{-26}*1.06*10^{-10})^{1/2}\\K_{goal}=1.793*10^{-33}$

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3 years ago

When electricity flows through water, the water molecules split into molecules of hydrogen and oxygen gas. How many oxygen (O2)

ikadub [295]

That would be one oxygen molecule.

5 0

3 years ago

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Under which conditions of temperature and pressure is a gas most soluble in water?

anyanavicka [17]

2. <span>High pressure and low temperature

Hope this helps </span>

4 0

3 years ago