Answer:
the two gliders collide, the mobile glider will transfer a bit of time to the fixed glider, which is why it comes out with a speed that is smaller than that of the bullet glider.
Explanation:
When the two gliders collide, the mobile glider will transfer a bit of time to the fixed glider, which is why it comes out with a speed that is smaller than that of the bullet glider.
Changes can occur that the gliders unite and move with a cosecant speed less than the initial one.
The whole process must be analyzed using conservation of the moment.
p₀ = m v₀
celestines que clash case
p_f = (m + M) v
po = pf
m v₀ = (n + M) v
v = 
calculemos
v= 
v= 0.09 m/s
elastic shock case
p₀ = m v₀
p_f = m v₁ +M v₂
p₀ = p_f
m v₀ = m v₁ + m v₂
<span>a number assigned to an element in a chemical combo that represents the number of electrons lost or gained by atom of the element in the compound.</span>
Answer & Explanation:
The nerve impulses start in the dendrites then moves down the axon starting in the axon. Nerve impulses speed up the myelin sheath. Then through the nodes of ranvier speeding up action potential then at the axon terminal the electrical impulse goes through the synapse through electrical then chemical with neurotransmitters and electrical again back to a dendrite.
Answer: Option (1) 70 kJ
Explanation:
Given that;
melting point of the substance T₁ is 20°C
, Boiling point of the substance T₂ is 150°C
, heat of fusion L₁ is 3.5 x 10⁴ J/kg
, heat of vaporization L₂ is 7 x 10⁴ J/kg
, Specific heat in solid state C₁ is 600 J/kg.K
, Specific heat in liquid state C₂ is 1000 J/kg.K, Specific heat in gaseous state C₃ is 400 J/(kg.K)
, Mass of the substance m is 0.5 kg
, Initial temperature of the substance T₃ is 170°C
, Final temperature of the substance T₄ is 88°C
.
Now Heat given up by the substance to reach boiling point 150°C is
Q₁ = mC₃(T₃ - T₂)
Q₁ = (0.5)(400)(170 - 150)
Q₁ = 4000 J
Heat given up by the substance to turn into liquid from gaseous state at 150°C
Q₂ = mL₂
Q₂ = (0.5)(7x10⁴)
Q₂ = 35000 J
Heat given up by the substance to reach 88°C in liquid state from 150°C
Q₃ = mC₂(T₂ - T₄)
Q₃ = (0.5)(1000)(150 - 88)
Q₃ = 31000 J
Total heat given up by the substance
Q = Q₁ + Q₂ + Q₃
Q = 4000 + 35000 + 31000
Q = 70000 J
Q = 70 kJ
Therefore The quantity of heat given up by 0.50 kg of the substance when it is cooled from 170◦C to 88◦C, at a pressure of 1.0 atmosphere, is closest to 70 kJ
Answer:
Option (4)
Explanation:
There are two types of collision.
Perfectly elastic collision: the collision in which the momentum and kinetic energy is conserved. There is no loss of energy in other forms of energy.
Perfectly plastic collision: The collision in which the momentum is conserved and kinetic energy is not conserved. The two bodies stick after the collision.
Here, the bullet hits the block and then embedded in the block, it is the example of plastic collision.
