The normal force decreases, this is the frictional force. It will be counteracted by the force which accelerates the brick to slide downward opposite to the end where the board is raised. As the angle increases the force acting upon the brick opposite to the normal force will decrease.

5 0

4 years ago

Stewart (70 Kg) is attracted to Ms. Little (60 Kg) who sits 2 m away. What is the gravitational attraction between them? G=6.67×

ikadub [295]

Happy Holidays!

We can use the following equation to solve for the gravitational force:

$\large\boxed{F_g = G\frac{m_1m_2}{r^2}}$

Fg = force due to gravity (N)

G = Gravitational constant

m1,m2 = masses of the objects (kg)

r = distance between the objects (m)

Plug in the given values into the equation:

$F_g = (6.67*10^{-11})\frac{(70)(60)}{(2)^2}} = \boxed{7.0 * 10^{-8}N}$

7 0

3 years ago