A machine does 1000 J of output work when 2000 J of work is input. THe efficiency is
1 answer:
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Answer:
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answer :
20.16 v
Explanation:
The reading of the voltmeter at the instant the switch returns to position a
L = 5H
i ( current through inductor ) = 1/L ∫ V(t) d(t) + Vo
= 1/5 ∫ 3*10^-3 d(t) + 0 = 0.6 * 10^-3 t
iL ( 1.6 s ) = 0.6 * 10^-3 * 1.6 = 0.96 mA
Rm ( resistance ) = 21 * 1000 = 21 kΩ
The reading of the voltmeter ( V )
V = IR
= 0.96 mA * 21 k Ω = 20.16 v
Answer:
Mutual inductance will be
Explanation:
We have given induced current
Time is given as
We have to find the mutual inductance between the coils
Induced emf is given as e = 9 volt
We know that induced emf is given by