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3 years ago

When we touch things, how close do atoms get together? Or does anything touch anything else?? Full answer Please 50 - 100 words

2 answers:

8 0

Basically, we don't touch anything. We are always about an atom above the ground. The atoms in our body are very far apart. For example, if you made every atom in every human body touch then the whole earth's population could fit on a sugar cube. This is called the Pym law. The only reason I can't put my hand through the computer right now is since there is always one layer of electrons outlining our body. So the electrons stop us from falling into the center of the earth.

kkurt [141]3 years ago

3 0

Well, im pretty sure that when we do touch eachother, the atoms themselves are touching. idk if this is what ur looking for but hope this helps.

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What is the relationship between mass and weight in physics?

Alex_Xolod [135]

We are aware that weight is the product of applied gravitational force and mass. W = MG thus, where W represents the weight, M the mass, and G the gravitational force. As a result, it might also mean that "an object's weight is directly proportionate to its mass."

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The kilogram is the primary mass unit in the SI (kg).
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The force exerted on an object by gravity is known as the weight of the object in science and engineering.
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7 0

2 years ago

Two resistors, R1 and R2, are connected

marusya05 [52]

Answer:

18 ohms

Explanation:

V = I(R1 + R2)

5V = (0.167A)(12 ohms + R2)

Solving for R2

R2 = 18 ohms

3 0

3 years ago

What happens when velocity and acceleration are at right angles to each other

photoshop1234 [79]

You get circular motion, where the acceleration is pointing towards the center of the circle, as long as they are constant, and not fluctuating.

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3 years ago

Biologists use ball-and-stick models to study complex molecules by representing atoms with balls and bonds with sticks. DNA is a

AleksAgata [21]

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3 years ago

In one of the classic nuclear physics experiments at the beginning of the 20th century, an alpha particle was accelerated toward

Vladimir79 [104]

Answer:

The answer is " $1.01 \times 10^{-13}$ "

Explanation:

Using the law of conservation for energy. Equating the kinetic energy to the potential energy.

$KE=U=\frac{kqq'}{r}\\\\$

Calculating the closest distance:

$\to r=\frac{kqq'}{KE}\\\\$

$=\frac{k(2e)(79e)}{KE}\\\\=\frac{k(2)(79)e^2}{KE}\\\\=\frac{9.0\times 10^9 \ N \cdot \frac{m^2}{c}(2)(79)(1.6 \times10^{-19} \ C)^2}{(2.25\ meV) (\frac{1.6 \times 10^{-13} \ J}{1 \ MeV})}\\\\$

$=\frac{9.0\times 10^9 \times 2\times 79\times 1.6 \times10^{-19}\times 1.6 \times10^{-19} }{(2.25 \times 1.6 \times 10^{-13}) }\\\\=\frac{3,640.32\times 10^{-29}}{3.6 \times 10^{-13} }\\\\=\frac{3,640.32}{3.6} \times 10^{-16}\\\\=1011.2 \times 10^{-16}\\\\=1.01 \times 10^{-13}$

5 0

3 years ago