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zloy xaker [14]
3 years ago
12

What is the working principle of an electric motor?

Physics
2 answers:
slava [35]3 years ago
5 0
The answer B homie trust
Leni [432]3 years ago
3 0
The answer is b have a nice day
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What is the force of a lead ball that starts with a momentum of 7 kg*m/s and end with a momentum of 22 kg*m/s over a time of 31
Gwar [14]

Answer:

F = 0.483 N

Explanation:

Initial momentum, P_i= 7\ kg-m/s

Final momentum, P_f= 22\ kg-m/s

Time, t = 31 s

We need to find the force of a lead ball. We can use here the impulse momentum theorem.

\text{Change in momentum}=F\times t

F is force

P_f-P_i=Ft\\\\F=\dfrac{P_f-P_i}{t}\\\\F=\dfrac{22-7}{31}\\\\F=0.483\ N

So, the force is 0.483 N.

6 0
3 years ago
The figure shows a positive charge placed in a uniform electric field. Is the force exerted on the +1 C charge directed up or do
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Answer:

the answer is down on e2020

Explanation:

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3 years ago
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Red, green, and blue light rays each enter a drop of water from the same direction.Which light ray's path through the drop will
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Blue light will bend more than the others because it has a slightly greater refractive index. This is because blue light has a shorter wavelength and more energy, meaning it has to slow down more than the others when it hits the water.
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3 years ago
A EXAMPLE OF WHEN BOTH PHYSICAL CHANGE AND CHEMICAL CHANGE OCCUR 3 EXAMPLES
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Answer:

I know 1, that is in the case of a burning of a candle.

Explanation:

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3 years ago
A subway train starts from rest at a station and accelerates at a rate of 1.68 m/s2 for 14.2 s. It runs at constant speed for 68
liubo4ka [24]

Answer:

total distance = 1868.478 m

Explanation:

given data

accelerate = 1.68 m/s²

time = 14.2 s

constant time = 68 s

speed = 3.70 m/s²

to find out

total distance

solution

we know train start at rest so final velocity will be after 14 .2 s is

velocity final = acceleration × time      ..............1

final velocity = 1.68 × 14.2

final velocity = 23.856 m/s²

and for stop train we need time that is

final velocity = u + at

23.856 = 0 + 3.70(t)

t = 6.44 s

and

distance = ut + 1/2 × at²     ...........2

here u is initial velocity and t is time for 14.2 sec

distance 1 = 0 + 1/2 × 1.68 (14.2)²

distance 1 = 169.37 m

and

distance for 68 sec

distance 2= final velocity × time

distance 2= 23.856 × 68

distance 2 = 1622.208 m

and

distance for 6.44 sec

distance 3 = ut + 1/2 × at²

distance 3 = 23.856(6.44) - 0.5 (3.70) (6.44)²

distance 3 = 76.90 m

so

total distance = distance 1 + distance 2 + distance 3

total distance = 169.37 + 1622.208 + 76.90

total distance = 1868.478 m

7 0
3 years ago
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