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bija089 [108]
3 years ago
14

Name four products of incomplete combustion

Chemistry
1 answer:
aalyn [17]3 years ago
5 0

Answer: The products are carbon monoxide, water and carbon.

Explanation:

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Based on the solubility observations, which of the following pairs of cations could be distinguished by the addition of sodium c
Licemer1 [7]

Based on the solubility observations, barium & aluminum could be distinguished by the addition of sodium chloride to the solutions.

<h3>What happens when NaCl is added to a solution?</h3>
  • The ionic link that held sodium and chloride ions together is broken when water molecules force the ions apart.
  • The sodium and chloride atoms are encircled by water molecules after the salt compounds are separated. After that, the salt dissolves and forms a homogenous solution.
  • In order to keep patients from dehydrating, sodium chloride, an important nutrient, is employed in healthcare. It is employed as a spice to improve flavor and as a food preservative. Additionally, sodium chloride is employed in the production of polymers and other goods. Additionally, it is used to de-ice sidewalks and roadways.
  • Adding water to sodium chloride results in a physical change because no new product is created.

Learn more about sodium chloride added to a solution refer to :

brainly.com/question/28092739

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7 0
1 year ago
Structural strength and stability
Karo-lina-s [1.5K]
Strength, the capacity of the invi elements 
8 0
3 years ago
A 825 g iron block is heated to 352 degrees C and is placed in an insulated container (of negligible heat capacity) containing 4
Stella [2.4K]

Answer : The final equilibrium temperature of the water and iron is, 537.12 K

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

c_1 = specific heat of iron =  560 J/(kg.K)

c_1 = specific heat of water = 4186 J/(kg.K)

m_1 = mass of iron = 825 g

m_2 = mass of water = 40 g

T_f = final temperature of water and iron = ?

T_1 = initial temperature of iron = 352^oC=273+352=625K

T_2 = initial temperature of water = 20^oC=273+20=293K

Now put all the given values in the above formula, we get:

(825\times 10^{-3}kg)\times 560J/(kg.K)\times (T_f-625K)=-(40\times 10^{-3}kg)\times 4186J/(kg.K)\times (T_f-293K)

T_f=537.12K

Therefore, the final equilibrium temperature of the water and iron is, 537.12 K

8 0
3 years ago
PLEASE HELP
nata0808 [166]

Answer:

Is this math? Cause as a fourth grader, I can do Algebra, but not this.

Explanation:

7 0
2 years ago
When a 10 mL graduated cylinder is filled to the 10 mL mark, the mass of the water was measured to be 10.085 g at 20ºC. If the d
Arte-miy333 [17]
The percentage error is the error of the measured value to the true value. To find he percent error, the equation is as follows:

Percent error = |Measured Value - True Value|/True Value  * 100
The || is needed to get the absolute value of the difference. Substituting the values,

Percent error = |(10.085 g/10 mL) - 0.9975 g/mL|/<span>0.9975 g/mL  * 100
</span><em>Percent error = 1.1% </em>
8 0
4 years ago
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