Answer:
it creates a gas called carbon dioxide. The gas begins to expand in the bottle and starts to inflate the balloon
Explanation:
Why does this happen? well, The faster-moving particles inside the bottle start to move faster and faster and soon they expand to fill the balloon.
Answer: 7840N
Explanation:
Given that
Potential energy = ?
Mass of sled = 20-kg
Distance = 40 meters
Acceleration due to gravity = 9.8m/s^2
Recall that potential energy is the energy possessed by a body at rest
i.e potential energy = mass m x acceleration due to gravity g x distance h
P.E = mgh
P.E = 20kg x 9.8m/s^2 x 40m
P.E = 7840N
Thus, the potential energy of the sled is 7840N
Answer:
Refractive motion is the impact of a light wave that travels from medium to medium in an angle away from normal, where the direction of light varies. Light is refracted when it crosses the air-to-glass interface and moves slower.
Explanation:
Refractive motion is the impact of a light wave that travels from medium to medium in an angle away from normal, where the direction of light varies. Light is refracted when it crosses the air-to-glass interface and moves slower.
Hope this helps.
<span>When a pendulum is at the center position ...
-- it has zero potential energy
-- if it is moving, then it has some kinetic energy
-- if it is moving, then the center position is where it has the most kinetic energy </span>
Answer:

Explanation:
The work done on the object at rest is all converted into kinetic energy, so we can write

Or, re-arranging for v,

where
v is the final speed of the object
W is the work done
m is the object's mass
If the work done on the object is doubled, we have W' = 2W. Substituting into the previous formula, we can find the new final speed of the object:

So, the new speed of the object is
.