Explanation:
First, we need to calculate the number of moles of sodium carbonate we have in a 25 g sample. To calculate this, we will
find the molar mass of sodium carbonate (Na2CO3):
⇒ 2 × Molar mass of sodium + Molar mass of carbon + 3×molar mass of oxygen
⇒ 2 × 23 + 12 + 3 × 16
⇒ 46 + 12 + 48
⇒ 106g/mol
Thus, the molar mass of Na2CO3 is 106g/mol.
Therefore, number of moles = 25 ÷ 106
=> 0.2358 mol
Now, we know that every mole of Na2CO3 have 0.2358 moles of Na+ ions. Hence, total moles of Na2CO3 is 0.4716 moles
Number of ions present = 6.022 × 1023 × 0.4716 mol = 2.84 × 1023ions
We will see that the volume of the unit cell is 144,070,699.06 pm^3
<h3>
How to get the volume of a body-centered cubic unit cell?</h3>
In a body-centered cubic unit cell, the side length of the cube is given as:
Where R is the radius of the atom.
And the volume of a cube is the side length cubed, then we can see that the volume of our cube will be:
Solving that we get:
This is the approximated volume of the unit cell.
If you want to learn more about unit cell structures, you can read:
brainly.com/question/13110055
A chemical bond that is formed when two atoms share electrons is called a covalent bond :)
Answer:
Explanation:
The Avagadro constant = 6.022 x 10²³ denotes the no of molecules in one mole of the substance
Regarding Sulphur Dioxide, the molar mass is 64.
Hence 44 g means 44/64 mole of SO2
So no of molecules in 44g of SO2 = 6.022 x 10²³ x 44/64
On simplification,
11/16 x 6.022 x 10²³ molecules are present in 44g of SO2
