1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
gizmo_the_mogwai [7]
4 years ago
10

The process n01 → p11 + β−10 n 0 1 → p 1 1 + β - 1 0 represents a(n) _____.

Chemistry
1 answer:
polet [3.4K]4 years ago
5 0

Answer:

  • <u><em>beta decay</em></u>

Explanation:

The <em>process</em> is represented by the nuclear equation:

  • ^1_0n → ^1_1p+^0_{-1}\beta

Where:

  • n represents a neutron,
  • p represents a proton, and
  • β represents an electron.

The superscripts to the leff of each symbol is the mass number (number of protons and neutrons), and the subscript to the left means the atomic number (number of protons).

Then, in this process a neutron is being transformed into a proton by the emssion of an electron (from inside the nucleus of the atom).

This electron is named beta (β) particle, and the process is called <u><em>beta decay</em></u>, because the neutron is changing into other subatomic particles.

You might be interested in
What is a molarity a measurement
USPshnik [31]

Answer:

Molarity indicates the number of moles of solute per liter of solution and is one of the most common units used to measure the concentration of a solution.

Explanation:

8 0
4 years ago
Differentiate between group and period​
Katarina [22]

Answer:

A group is a vertical column of elements on the periodic table whereas a period is a horizontal row of elements on the periodic table.

4 0
3 years ago
Read 2 more answers
The equilibrium constant is given for one of the reactions below.
Cerrena [4.2K]

Answer:

12.7551

Explanation:

The given chemical equation follows:

2HD(g)\rightarrow H_2(g)+D_2(g)

The equilibrium constant for the above equation is 0.28.

We need to calculate the equilibrium constant for the reverse equation of above chemical equation, which is:

2H_2(g)+2D_2(g)\rightarrow 4HD(g)

The equilibrium constant for the reverse reaction will be the reciprocal of the initial reaction.

If the equation is multiplied by a factor of '2', the equilibrium constant of the reverse reaction will be the square of the equilibrium constant  of initial reaction.

The value of equilibrium constant for reverse reaction is:

K_{eq}'=(\frac{1}{0.28})^2

<u>Hence, the value of equilibrium constant for reverse reaction is 12.7551.</u>

3 0
4 years ago
If the ka of a monoprotic weak acid is 5.4 × 10-6, what is the ph of a 0.14 m solution of this acid?
Aleks [24]

pH = 2.1

Let HA (aq) resembles the acid; as a weak acid (a small value of K_{a}) HA would partially dissociate to produce protons H^{+} and A^{-}, its conjugate base. Let the final proton concentration (i.e., [H^{+}]) be x. (Apparently x \ge 0) Construct the following RICE table:

\left\begin{array}{cccccc}\text{R}&HA(aq)&\rightleftharpoons&H^{+}(aq) &+ &A^{-}(aq)\\\text{I} & 0.14 \; \text{M} & &\\\text{C}&-x \; \text{M}& &+x \; \text{M} & & +x \; \text{M}\\E & (0.14 - x)\; \text{M} & & x \; \text{M} & &\+x \; \text{M}\end{array}\right

By definition, (all concentrations are under equilibrium condition)

\left\begin{array}{ccc}K_{a}&=&[H^{+}] \cdot [A^{-}] / [HA]\\&=&x^{2} /(0.14 - x)\end{array}\right

It is given that

K_a = 5.4 \cdot 10^{-6}

Equating and simplifying the two expressions gives a quadratic equation; solve the equation for x gives:

x^2 = 5.4 \cdot 10^{-6} \cdot (14 - x) \\x^2 + 5.4 \cdot 10^{-6} \cdot 14 \cdot x - 5.4 \cdot 10^{-6} \cdot 14 = 0 \\x = 0.0087 \; \text{M} \; (x \ge 0)

The pH of a solutions equals the opposite of the logarithm of its proton concentration to base 10; thus for this particular solution

\text{pH} = -\text{ln(}[H^{+}]\text{)} / \text{ln(}10\text{)} = 2.1

7 0
4 years ago
Why does silicon in silicon dioxide bond with 4 oxygen atoms and not 2?
Elis [28]

Answer:

Silicon does not form double bonds with oxygen, whereas carbon is capable of forming double bonds with oxygen. While the carbon dioxide molecular structure is linear, the silicon dioxide has an extended, different covalent structure.

Explanation:

If the sizes of the atoms of Silicon (Si) and Carbon (C) are compared to each other, the Si atoms are larger than carbon - which implies that the Si-O bonds will be longer than the C-O bonds. As a result, the p orbitals present on the Si and O atoms aren't very near to each other, in order to get together for the required overlap sideways which could have formed a stable pi bond. Hence, Silicon forms only single covalent bonds with Oxygen in silicon dioxide, in the form of a diamond structure with each Si atom being connected to its four neighbouring atoms through an O atom.

On the other hand, in the case of carbon dioxide, C is perfectly capable of forming double bonds with O. The different p orbitals are brought close together, resulting in a sideways overlap that leads to two pi bonds, twisted at a right angle to each other. As a result, the Carbon in carbon dioxide bonds with 2 oxygen atoms but not 4.

5 0
4 years ago
Other questions:
  • Step by step instructions please
    5·1 answer
  • Which of the following is an example of the conversion of electrical energy to electromagnetic energy?
    9·2 answers
  • The main function of which system is to help protect inner organs from being damaged by an outside force? *
    10·1 answer
  • A community includes
    15·2 answers
  • Two non-metals that have less than 10 protons
    5·1 answer
  • EMERGENCY OR I WILL FAIL PLS HELP I WILL MARK BRAINLIEST!!!!
    5·1 answer
  • Why is dilute tetraoxosulphate(VI) acid not suitable for preparing carbon monooxide​
    9·1 answer
  • Which prefix is the smallest?
    9·1 answer
  • How might the structure of an atom be modeled
    14·1 answer
  • If any girl want to be my girlfrîend?​
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!