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gizmo_the_mogwai [7]
3 years ago
10

The process n01 → p11 + β−10 n 0 1 → p 1 1 + β - 1 0 represents a(n) _____.

Chemistry
1 answer:
polet [3.4K]3 years ago
5 0

Answer:

  • <u><em>beta decay</em></u>

Explanation:

The <em>process</em> is represented by the nuclear equation:

  • ^1_0n → ^1_1p+^0_{-1}\beta

Where:

  • n represents a neutron,
  • p represents a proton, and
  • β represents an electron.

The superscripts to the leff of each symbol is the mass number (number of protons and neutrons), and the subscript to the left means the atomic number (number of protons).

Then, in this process a neutron is being transformed into a proton by the emssion of an electron (from inside the nucleus of the atom).

This electron is named beta (β) particle, and the process is called <u><em>beta decay</em></u>, because the neutron is changing into other subatomic particles.

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Write the net ionic equation for the reaction of aqueous solutions of ammonium chloride and iron(III) hydroxide.
vagabundo [1.1K]

Answer:

Fe(OH)_3(s)\rightarrow Fe^{3+}(aq)+3OH^-(aq)

Explanation:

Hello.

In this case, for the reaction between aqueous solutions of ammonium chloride and iron (III) hydroxide, we have the following complete molecular reaction:

3NH_4Cl(aq)+Fe(OH)_3(s)\rightarrow 3NH_4OH+FeCl_3

And the full ionic equation, taking into account that the iron (III) hydroxide cannot be dissolved as it is insoluble in water:

3NH_4^+(aq)+3Cl^-(aq)+Fe(OH)_3(s)\rightarrow 3NH_4^+(aq)+3OH^-(aq)+Fe^{3+}(aq)+3Cl^-(aq)

Finally, the net ionic equation, considering that spectator ions are NH₄⁺, Cl⁻ as they are both the left and right side, therefore, the net ionic equation is:

Fe(OH)_3(s)\rightarrow Fe^{3+}(aq)+3OH^-(aq)

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(6 points) Calculate the maximum number of moles and grams of H2S that can form when 158 g of aluminum sulfide reacts with 131 g
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Explanation:

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If 1 mole of Al2S3 yields 3 moles of H2S

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Number of moles of water = 131g/18gmol-1= 7.3 moles

6 moles of water yields 3 moles of H2S

7.3 moles of water will yield 7.3 × 3/6 = 3.65 moles of H2S

3.65 moles × 34 gmol-1 =124.1 g

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