The classifications of the functions are
- A vertical stretch --- p(x) = 4f(x)
- A vertical compression --- g(x) = 0.65f(x)
- A horizontal stretch --- k(x) = f(0.5x)
- A horizontal compression --- h(x) = f(14x)
<h3>How to classify each function accordingly?</h3>
The categories of the functions are given as
- A vertical stretch
- A vertical compression
- A horizontal stretch
- A horizontal compression
The general rules of the above definitions are:
- A vertical stretch --- g(x) = a f(x) if |a| > 1
- A vertical compression --- g(x) = a f(x) if 0 < |a| < 1
- A horizontal stretch --- g(x) = f(bx) if 0 < |b| < 1
- A horizontal compression --- g(x) = f(bx) if |b| > 1
Using the above rules and highlights, we have the classifications of the functions to be
- A vertical stretch --- p(x) = 4f(x)
- A vertical compression --- g(x) = 0.65f(x)
- A horizontal stretch --- k(x) = f(0.5x)
- A horizontal compression --- h(x) = f(14x)
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258/300 u have to simplify 300 and 258 r both divisible by 3, 258/300 divided by 3/3 equals 86/100, as a decimal this is 0.86 and as a percent is is 86%
It takes one pipe x minutes, the other pipe x+3 minutes
the portion filled per minute is by one pipe is 1/x, by the second pipe 1/(x+3)
when two pipes running together:
3&1/3[1/x+1/(x+3)] =1, 1 means the whole cistern
solve for x: 3&1/3(x+3) +3 1/3(x)=x(x+3)
6 &2/3 x +10 =x^2+3x
x^2- (3&2/3) x-10=0
3x^2-11x-30=0
this cannot be factored, so use the quadratic equation:
x is about 5.5
x+3=8.5
