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kkurt [141]
2 years ago
13

Select all of the values for a that would make the inequality 2x > 10 true.

Mathematics
1 answer:
babunello [35]2 years ago
6 0

Answer:

Step-by-step explanation:

2x > 10       Divide by 2

2x/2 >10/2

x > 5

x cannot be 5 or anything smaller.

In English, x >5 reads as x must be greater than 5. (It can't be equal to 5 because 5 is not greater than 5)

The only two items that work are

8 which is greater than 5 and

30 which is also greater than 5

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PLEASE HELP
Westkost [7]

\\ \sf\longmapsto \dfrac{2}{3}x=10

\\ \sf\longmapsto \dfrac{2x}{3}=10

\\ \sf\longmapsto 2x=3(10)

\\ \sf\longmapsto 2x=30

\\ \sf\longmapsto x=\dfrac{30}{2}

\\ \sf\longmapsto x=15

8 0
3 years ago
Read 2 more answers
an art teacher has 1 1/2 pounds of red clay and 3/4 pound of yellow clay.The teacher mixes the red clay and yellow clay together
Nataly [62]
Well, seeing as how she mixed the clay, she has a total of 2 2/8 pounds clay (unsimplified). Although we don't know how many students she has in one class, with simple division of this number we can figure out how many student can finish the project. Removing the 2/8, we can already tell 2 students can do it, so that's a start. Now to divide the 2 pounds into 8ths. Each pound is enough for 8 students, so the 2 pounds totals to 16. Now add the extra 2 students, it's 18 total students. Hope I explained it well enough!
7 0
3 years ago
What is the answer to <br> 20/$23.80
kari74 [83]

Answer: .84

Step-by-step explanation:

5 0
3 years ago
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If a huddle of 72 Penguins break apart how many different ways can the penguin form equal groups
navik [9.2K]
3 differnt ways i do believe 
7 0
3 years ago
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But for real now I need help please thanks in advance
Alik [6]

Answer:

B

Step-by-step explanation:

Given endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is

( \frac{x_{1}+x_{2}  }{2} , \frac{y_{1}+y_{2}  }{2} )

Here (x₁, y₁ ) = (2, 3) and (x₂, y₂ ) = (10, 3) , then

midpoint = ( \frac{2+10}{2}, \frac{3+3}{2} ) = ( \frac{12}{2}, \frac{6}{2} ) = (6, 3 ) → B

8 0
2 years ago
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