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kkurt [141]
3 years ago
13

Select all of the values for a that would make the inequality 2x > 10 true.

Mathematics
1 answer:
babunello [35]3 years ago
6 0

Answer:

Step-by-step explanation:

2x > 10       Divide by 2

2x/2 >10/2

x > 5

x cannot be 5 or anything smaller.

In English, x >5 reads as x must be greater than 5. (It can't be equal to 5 because 5 is not greater than 5)

The only two items that work are

8 which is greater than 5 and

30 which is also greater than 5

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How many fourths are in 4 1/4? Use your answer to rewrite 4 1/4 in the form ?/4
hoa [83]

17/4 because you have to do 4x4 +1 which equal 17 then make that an improper fraction.
5 0
3 years ago
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Point GG is located at (1,-2)(1,−2) on the coordinate plane. Point GG is reflected over the yy-axis to create point G'G
yan [13]

Step-by-step explanation:

starting at (1,-2) the point will move to the left 2 to be reflected over the y-axis and will then be at (-1,-2). then reflecting over the x-axis will move it up 4 and end up at (-1,2).

4 0
2 years ago
What's the answer to this
shutvik [7]

you would first have to multiply 20% by 3.24 and then youll get 0.648 then you subtract 3.24 by 0.648 and get 2.60. Then multiply 20% by 3.99 and get 0.798 then subtract 3.99 by 0.798 and get 3.19 then add 2.60 with 3.19 to get 5.79. 5.79 is how much she spent with 20% off

3 0
3 years ago
The problem below has been solved incorrectly. Identify and explain the error.
mylen [45]

Answer:

If you look over the steps you can see that until 4x + x + 3 = 18, evertything is dandy. But the step after that 4x + x =21 seems a bit fishy.

Think about it they subtract 3 from both sides so the first side is correct

4x + x, but they added 3 to the other side:

(4x+x+3) - 3 = 18 - 3\\4x+x = 15

not

4x+x = 21

Then we solve for 4x + x = 15

5x = 15\\x = \frac{15}{5} \\x = 3

To solve for y we use :

y = x+3

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so (3,6) is the right answer

7 0
3 years ago
Any idea ? I need help
trasher [3.6K]
Use the Pythagorean Theorem:
a^2 + b^2= c^2

a= one side= 68 mi
b= second side= 80 mi
c= hypotenuse= Greenville to Columbia mi


a^2 + b^2= c^2

68^2 + 80^2= c^2
square each number

4,624 + 6,400= c^2

11,024= c^2
take square root of both sides

104.995 mi= c


ANSWER: The distance from Greenville to Columbia is 104.995 miles (rounded to 105 miles).

Hope this helps! :)
3 0
3 years ago
Read 2 more answers
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