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2 years ago

An object at rest accelerates at 6.58 m/s2 for 4.74 s final velocity

Physics

1 answer:

Natali [406]2 years ago

6 0

Answer:

31.2m/s

Explanation:

final velocity = initial velocity + acceleration • time

final velocity = 0 m/s + 6.58m/s/s • 4.74 s

final velocity = 31.2 m/s

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A particle with charge 7.76×10^(−8)C is moving in a region where there is a uniform 0.700 T magnetic field in the +x-direction.

kodGreya [7K]

Answer:

The z-component of the force is $\= F_z = 0.00141 \ N$

Explanation:

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$v_y = -5.85*10^{4}\ \r k \ m/s$

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$\= F = q (\= v X \= B )$

So we have

$\= F = q ( v_x \r i + v_y \r j + v_z \r k ) \ \ X \ ( \= B i)$

$\= F = q (v_y B(-\r k) + v_z B\r j)$

substituting values

$\= F = (7.7 *10^{-8})([ (-2.61*10^{4}) (0.700)](-\r z) + [(5.58*10^{4}) (0.700)]\r y)$

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Note : The cross-multiplication template of unit vectors is shown on the first uploaded image ( From Wikibooks ).

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Keith_Richards [23]

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KIM [24]

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