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SCORPION-xisa [38]
3 years ago
12

Thermal energy generated by the electrical resistance of a 5-mm-diameter and 4-m-long bare cable is dissipated to the surroundin

g air at 20°C. The voltage drop and the electric current across the cable in steady operation are measured to be 60 V and 1.5 A, respectively. Disregarding radiation, estimate the surface temperature of the cable. Evaluate air properties at a film temperature of 60°C and 1 atm pressure. Is this a good assumption?

Engineering
1 answer:
ella [17]3 years ago
6 0

Answer:

surface temperature = 128.74⁰c

Explanation:

Given data

diameter of cable = 5 mm = 0.005 m

length of cable = 4 m

T∞ ( surrounding temperature ) = 20⁰c

voltage drop across cable ( dv )= 60 V

current across cable = 1.5 A

attached to this answer is the comprehensive analysis and solution to the problem.

The assumption made is not a good one since the calculated Ts ( surface temperature ) is very much different from the assumed Ts

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96/64 reduced to its lowest term
Marina CMI [18]

Answer:

3/2

Explanation:

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2 years ago
soccer is also called association football" A soccer ball is a sphere, with circumference of 70 centimeters. in developing a new
timama [110]

Answer: Weight on Mars = 0.02593N

Explanation:

Given; Circumference C of Sphere = 70cm = 0.7m,

Specific Gravity S. G. of material = 1.21,

acceleration due to gravity in the Mars gm = 3.7m/s^2

We know that Weight W = mass m × acceleration due to gravity.

Let the Weight in on the Mars be Wm.

Wm = m × gm

Since we are given gm, we need to calculate for m. (Note that mass m is the same everywhere)

But mass = specific gravity × volume

Since we know the specific gravity, let's go ahead to calculate for the volume of the ball.

We know that Volume of a Sphere V = (4/3)πr^3

To get r, we know that C = 2πr

Therefore, r = C/(2π) = 0.7/(2π) = (7/10)/2π = 7/20π (in meters)

V = (4/3)*π×(7/20π)^3 = 343/6000π^2 (in meter^3)

m = 343/6000π^2 × 1.21 = 7.01×10^(-3)kg

Wm = 7.01×10^(-3) × 3.7 = 0.02593N

8 0
3 years ago
Design a 3-bit binary counter using S-R flip flops.
Helen [10]

Answer:

This is an asynchrnous 3-bit counter. Just note that this design is different and works differently than its synchronous counterpart. It's an easier design than its synchronous counterpart, and is not as reliable because it has delays.

3 0
3 years ago
Water flows with an average speed of 6.5 ft/s in a rectangular channel having a width of 5 ft The depth of the water is 2 ft.
lisov135 [29]

Answer:

specific energy  = 2.65 ft

y2 = 1.48 ft  

Explanation:

given data

average speed v = 6.5 ft/s

width = 5 ft

depth of the water y = 2 ft

solution

we get here specific energy that is express as

specific energy = y + \frac{v^2}{2g}     ...............1

put here value and we get

specific energy = 2 + \frac{6.5^2}{2\times 9.8\times 3.281}  

specific energy  = 2.65 ft

and

alternate depth is

y2 = \frac{y1}{2} \times (-1+\sqrt{1+8Fr^2})  

and

here Fr² = \frac{v1}{\sqrt{gy}}  = \frac{6.5}{\sqrt{32.8\times 2}}  

Fr² = 0.8025

put here value and we get

y2 = \frac{2}{2} \times (-1+\sqrt{1+8\times 0.8025^2})

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7 0
3 years ago
Compute the volume percent of graphite, VGr, in a 3.9 wt% C cast iron, assuming that all the carbon exists as the graphite phase
kicyunya [14]

Answer:

Vgr = 0.122 = 12.2 vol %

Explanation:

Density of ferrite = 7.9 g/cm^3

Density of graphite = 2.3 g/cm^3

<u>compute the volume percent of graphite </u>

for a 3.9 wt% cast Iron

W∝ =  (100 - 3.9) / ( 100 -0 ) = 0.961

Wgr = ( 3.9 - 0 ) / ( 100 - 0 ) = 0.039

Next convert the weight fraction to volume fraction using the equation attached below

Vgr = 0.122 = 12.2 vol %

6 0
3 years ago
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