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3 years ago

Order of Design Process steps ?

Engineering

1 answer:

gregori [183]3 years ago

5 0

Answer:

The five stages of Design Thinking, according to d.school, are as follows: Empathise, Define , Ideate, Prototype, and Test. Let's take a closer look at the five different stages of Design Thinking

Explanation:

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A 0.4-W cylindrical electronic component with diameter 0.3 cm and length 1.8 cm and mounted on a circuit board is cooled by air

Katyanochek1 [597]

Answer:

The surface temperature of the component 54.6 degrees celsius.

Explanation:

Please see attachment.

7 0

3 years ago

You will write a program estimate that uses a training data set to learn weights for a set of house attributes, and then applies

gizmo_the_mogwai [7]

Answer:

I can share a link to answer since the code is to long to be contained here. the code is on github

https://github.com/arafatm/edu_coursera_machine_learning_1_foundations/blob/master/code/02.01.predicting.house.prices.ipynb

5 0

3 years ago

Assume that each atom is a hard sphere with the surface of each atom in contact with the surface of its nearest neighbor. Determ

deff fn [24]

Answer:

The classification of the concern is listed in the interpretation segment below.

Explanation:

(a)...

Simple cubic lattice

$a=2r$

Now,

The unit cell volume will be:

$=a^3$

$=(2r)^3$

$=8r^3$

At one atom per cell, atom volume will be:

$=(1)\times (\frac{4 \pi r^3}{3})$

Then the ratio will be:

$Ratio=\frac{\frac{4 \pi r^3}{3}}{8r^3}\times 100 \ percent$

$=52.4 \ percent$

(b)...

Diamond lattice

The body diagonal will be:

$d=8r=a\sqrt{3}$

$a=\frac{8}{\sqrt{3}}r$

The unit cell volume will be:

$=a^1$

$=(\frac{8r}{\sqrt{3}})^1$

At eight atom per cell, the atom volume will be:

$=8(\frac{4 \pi r^1}{3})$

Then the Ratio will be:

$Ratio=\frac{8(\frac{4 \pi r^1}{3})}{(\frac{8r}{\sqrt{3}})^1}\times 100 \ percent$

$=34 \ percent$

Note: percent = %

5 0

3 years ago

'Energy' has the potential to:

Kazeer [188]

answer:

Energy' has the potential to:do work

b.do work

6 0

2 years ago

An equilibrium mixture of 3 kmol of CO, 2.5 kmol of O2, and 8 kmol of N2 is heated to 2600 K at a pressure of 5 atm. Determine t

garri49 [273]

Answer:

$x_{CO}=0.0203\\x_{O_2}=0.0926\\x_{CO_2}=0.227\\x_{N_2}=0.660$

Explanation:

Hello,

In this case, we consider the reaction:

$CO(g)+\frac{1}{2} O_2(g)\rightleftharpoons CO_2$

For which the law of mass action is expressed as:

$Kp=\frac{n_{CO_2}}{n_{CO}*n_{O_2}^{1/2}} (\frac{P}{n_{Tot}} )^{1-1-1/2}$

Whereas the exponents are referred to the stoichiometric coefficients in the chemical reaction. Moreover, in table A-28 (Cengel's thermodynamics) the natural logarithm of the undergoing reaction at 2600 K is 2.801, thus:

$K=exp(2.801)=16.46$

In such a way, in terms of the change $x$ the equilibrium goes:

$16.46=\frac{x}{(3kmol-x)*(2.5kmol-0.5x)^{0.5}} (\frac{5}{13.5kmol-0.5x} )^{-0.5}$

Hence, solving for $x$ :

$x=2.754kmol$

Thus, the moles at equilibrium:

$n_{CO}=3-2.754=0.246kmol\\n_{O_2}=2.5-0.5(2.754)=1.123kmol\\n_{CO_2}=x=2.754kmol\\n_{N_2}=8kmol$

Finally the compositions:

$x_{CO}=\frac{0.246}{0.246+1.123+2.754+8} =0.0203\\\\x_{O_2}=\frac{1.123}{0.246+1.123+2.754+8} =0.0926\\\\x_{CO_2}=\frac{2.754}{0.246+1.123+2.754+8} =0.227\\\\x_{N_2}=\frac{8}{0.246+1.123+2.754+8} =0.660$

Best regards.

7 0

4 years ago