Both A and B technicians are correct because both might be used to test fuses, according to technician B.
<h3>What is continuity?</h3>
The behavior of a function at a certain point or section is described by continuity. The limit can be used to determine continuity.
From the question:
We can conclude:
The technician claims that you may check for continuity using both an ohmmeter and a self-powered test light. Both might be used to test fuses, according to technician B.
Thus, both A and B technicians are correct because both might be used to test fuses, according to technician B.
Technician A says both an ohmmeter and a self-powered test light may be used to test for continuity. Technician B says both may be used to test fuses. Who is correct?
Learn more about the continuity here:
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Answer:
Negative peer pressure and High-pressure expectations might be your answer.
Hope this helps :)
Answer:
b) journal book
Explanation:
A ledger is an account for recording balance sheet and income statement transaction entries like cash, investments, inventory and so on.
Before a transaction is posted into the ledger account after an accounting cycle, it is first written in the journal book, before it is then posted in the ledger account. The process of posting refers to the transferring of entries from the journal book to the ledger.
Answer:
See the attached diagram containing the detailed solution
Answer:
the life (N) of the specimen is 46400 cycles
Explanation:
given data
ultimate strength Su = 1600 MPa
stress amplitude σa = 900 MPa
to find out
life (N) of the specimen
solution
we first calculate the endurance limit of specimen Se i.e
Se = 0.5× Su .............1
Se = 0.5 × 1600
Se = 800 Mpa
and we know
Se for steel is 700 Mpa for Su ≥ 1400 Mpa
so we take endurance limit Se is = 700 Mpa
and strength of friction f = 0.77 for 232 ksi
because for Se 0.5 Su at 
cycle = (1600 × 0.145 ksi ) = 232
so here coefficient value (a) will be
a = 
a = 
a = 2168.3 Mpa
so
coefficient value (b) will be
a = -
log
b = -log
b = -0.0818
so no of cycle N is
N = 
put here value
N = 
N = 46400
the life (N) of the specimen is 46400 cycles
