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blsea [12.9K]
3 years ago
11

When different resistors are connected in parallel across an ideal battery, we can be certain that...

Physics
1 answer:
NeTakaya3 years ago
8 0

Answer:

<em>Explained Below.</em>

Explanation:

<em>Whenever the different resistors are fixed parallel along with an ideal battery , we can be certain that</em><em> </em><u><em>it carries the same potential difference across each of them. </em></u>

And potential difference is nothing but the energy that charge moves with. It can also be denoted as (p.d.) and potential difference is been calculated as volts that is been denoted as (V).

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Please help! This is due tomorrow and I absolutely need help.
zysi [14]

Answer:

Correct answer:  11. Total distance d = 200m ; 12. Vav = 3.63m/s ;

13. Total displacement Dt = 0m ; 14. V₂(10s-15s) = 0 m/s ;

15. V₃(15s-40s) = 4 m/s ; 16. V₁(0s-10s) = 6 m/s > V₄(40s-55s) = 2.67 m/s

Explanation:

The whole movement can be divided into four stages.

In the first stage the subject moves 60m in a positive direction for 10s,

in the other it is stationary for 5s, in the third it moves 100m in the opposite (negative) direction for 25s and in the fourth in the positive 40m for 15s.

11. Total distance = 60 + 0 + 100 + 40 = 200m

12. The formula for calculating the average speed (velocity) is

Vav = (S₁ + S₂ + S₃ + S₄) / (t₁ + t₂ + t₃ + t₄)

Vav = (60 + 0 + 100 + 40)/ (10 + 5 + 25 + 15) = 200/55 = 3.63 m/s

13. The movement started from the origin and ended at the origin

Total displacement is zero meters.

14. The speed between 10s and 15s is zero, because he did not move.

15. V₃ = S₃/t₃ = 100/25 = 4 m/s

16. V₁ = S₁/t₁ = 60/10 = 6 m/s   and V₄ = S₄/t₄ = 40/15 = 2.67 m/s

V₁ > V₄

God is with you!!!

4 0
3 years ago
How big is the international space station?
oee [108]
The dimensions of the completed ISS research facility will be approximately 356 feet (109 meters) by 240 feet (73 meters), or slightly larger than a football field. the ISS weighes around 450 tons (408,000 kg), or 450 times the weight of an average car.
3 0
3 years ago
40 POINTS EASY
11111nata11111 [884]
We know, Mechanical Energy = K.E. + P.E.
As ball is at ground, P.E. would be zero. But as it is in motion, it must have some K.E. and that is:

K.E. = 1/2 mv²
K.E. = 1/2 * 1 * 2²
K.E. = 4/2
K.E. = 2 J

In short, Your Answer would be Option B

Hope this helps!
7 0
3 years ago
Infer which group you would expect to contain element 117. Use the periodic table to help you answer this question.
Gre4nikov [31]

Answer:

halogen group

Explanation:

6 0
2 years ago
A ball thrown horizontally from a point 30.0 m above the ground strikes the ground after travelling a horizontal distance of 18.
AURORKA [14]

The components of the ball's position r at time t are

\begin{cases}r_x(t)=v_{0x}t\\v_y(t)=30.0-4.9t^2\end{cases}

The ball stops 18.0 m from where it began, so that

\begin{cases}18.0=v_{0x}t\\0=30.0-4.9t^2\end{cases}

From the second equation, we can show that the ball travels for about t=2.47 seconds, which means it was initially thrown with a horizontal velocity of

18.0\,\mathrm m=v_{0x}(2.47\,\mathrm s)\implies v_{0x}=7.29\,\dfrac{\mathrm m}{\mathrm s}

7 0
3 years ago
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