A liquid is a matter that neither has a fixed shape but fixed volume...in college really need to know this.
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The potential difference across the capacitor is 5 × 10∧4 volts and the energy stored in it is 1. 25 Joules
<h3>
What is the energy in a capacitor?</h3>
The energy stored in a capacitor is an electrostatic potential energy.
It is related to the charge(Q) and voltage (V) between the capacitor plates.
It is represented as 'U'.
<h3>
How to determine the potential difference</h3>
Formula:
Potential difference, V is the ratio of the charge to the capacitance of a capacitor.
It is calculated using:
V = Q ÷ C
Where Q = charge 5 × 10∧-5C and C = capacitance 10∧-9
Substitute the values into the equation
Potential difference, V = 5 × 10∧-5 ÷ 10∧-9 = 5 × 10∧4 volts
<h3>
How to determine the energy stored</h3>
Formula:
Energy, U = 1 ÷ 2 (QV)
Where Q= charge and V = potential difference across the capacitor
Energy, U = 1 ÷ 2 ( 5 × 10∧-5 × 5 × 10∧4)
= 0.5 × 25 × 10∧-1
= 0.5 × 2.5
= 1. 25 Joules
Therefore, the potential difference across the capacitor is 5 × 10∧4 volts and the energy stored in it is 1. 25 Joules
Learn more about capacitance here:
brainly.com/question/14883923
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In one quadrant there are 90 degrees.
A positive charge cause dosent your hair static up when that happens or no?
Answer:
The maximum length during the motion is 
Explanation:
From the question we are told that
The mass is 
The vertical spring length is 
The unstretched length is 
The initial speed is 
The new length of the spring 
The spring constant k is mathematically represented as

Where F is the force applied 
y is the difference in weight which is 
The negative sign is because the displacement of the spring (i.e its extension occurs against the force F)
Now substituting values accordingly


The elastic potential energy is given as 
where D is this the is the displacement
Since Energy is conserved the total elastic potential energy would be

Substituting value accordingly




So to obtain total length we would add the unstretched length
So we have
