Answer:If a bouncing ball has a total energy of 20 J and a kinetic energy of 5 J, the ball’s potential energy is 15J.
If the kinetic energy of the ball decreases, then the potential energy will Increase.
Explanation:
Explanation:
The end goal of this question is to find density. Density can be found using the following formula:
D=m/v
D=Density
m=mass
v=volume
Therefore we need mass and volume to find density. Mass is already given in the question as 142g. All we have left is volume. When a solid is placed in water in a graduated cylinder the volume goes up. This means if you subtract the volume after the metal was placed from before it was placed, you can find the volume of the metal. Therefore the volume of the metal is 40mL-20mL=20mL. However typically, volume is found in liters so the volume should be .04L-.02L=0.02L. Now that we have volume and mass we can find density using the formula d=m/v. So 142/.02=7,100 grams per liget or 7.1 kilograms per liter. This answer seems unrealistic so I would double check with your teacher about the question.
Hope I helped, 2Trash4U
<span>Deciduous forests have a long, warm growing season as one of four distinct seasons.There is abundant moisture.The soil typically is rich. The leaves dropped from trees provide a steady source of organic material for the soil. Many species live in the soil and break down the organic matter.Tree leaves are arranged in strata: canopy, understory, shrub, and ground. A great deal of light is therefore filtered out before it reaches the ground.With the dropping of their leaves during one season, trees stop photosynthesis and enter a dormant period.<span>Three main types of trees are characteristic of these forests: northern hardwood, central hardwood, and southeast pine and oak.
</span></span>
Answer:
B
Explanation:
First Law of thermodynamics says energy of the universe is constant and can only be changed in other forms of energy
Answer: -
280mg
Explanation: -
The chemical formula is C14H18N2O5
Molar mass of the compound = 12 x 14 + 1 x 18 + 14 x 2 + 16 x 5 = 294 gram
Number of nitrogen atoms present in the formula = 2
Mass of nitrogen present= 14 x 2 = 28 gram
Thus 294 gram of the compound has 28 gram.
Hence 2.95grams of the compound has (28 gram x 2.95 gram / 294 gram)
= 0.28 gram
= 280 mg
Thus 280 mg of nitrogen is present in 2.95 grams of C14H18N2O5