Answer:800N
Explanation:
Force of repulsion = kq1q2/r^2
Q1= 20*10^-6
Q2=100*10^-6
R=150cm=0.15m
K= 9*10^9
F= 2*10^-5*1*10^-4*9*10^9/(0.15)^2
F= 2*1*9*10^-5-4+9/(0.15)^2
F= 18*10^0/(0.15)^2
F=18/0.0225
F=800N
1. F
This phenomenon is in accordance with Newton's Third Law of Motion, which states that when a body exerts a force on a second body, the second body exerts a force of equal magnitude in the opposite direction on the first body. The masses of the bodies are irrelevant in this case.
Answer:
-main-sequence star
-protostar with jets
-contracting cloud trapping infrared light
-molecular-cloud fragment
Explanation:
The Life of a Star of about one Solar Mass. Small stars have a mass upto 1 1/2 times that of the Sun. Stars are planetary bodies that revolve in space. They are the combination of hydrogen and helium gases
seven main stages of a star formation are
A Giant Gas Cloud. A star begins life as a large cloud of gas. ...
A Protostar Is a Baby Star. ...
The T-Tauri Phase. ...
Main Sequence Stars. ...
Expansion into Red Giant. ...
Fusion of Heavier Elements. ...
Supernovae and Planetary Nebulae.
But ranking them according to the central temperature, from highest to lowest. will be
-main-sequence star
-protostar with jets
-contracting cloud trapping infrared light
-molecular-cloud fragment
<u>Answer:</u>
Ranks based on momentum are
<em>1. </em><em>1200 kg car going at 15 m/s.</em>
<em>2.</em><em> 15 kg meteor going at a speed of 100 m/s.</em>
<em>3. </em><em>100 kg person running at 5 m/s.</em>
<em>4.</em><em> 10000 kg train car at rest.</em>
<u>Explanation:</u>
Product of a body’s mass and velocity gives the value of its momentum. It is given by the equation
where is the mass of the object and is the velocity.
Calculating the values of momentum:
1. mass= 1200 kg, velocity= 15 m/s
2. mass= 15 kg, velocity= 1000 m/s
3. mass= 100 kg, velocity= 5 m/s
4. mass= 1000 kg, velocity= 0 m/s
