The mass of calcium hydroxide that is formed when 10.0 g of CaO reacts with 10.0 g of water is 13.024 grams
calculation
from the equation
CaO + H2O → Ca(OH)2,
1 moles of CaO reacted with 1 moles of H2O to form 1 moles of Ca(OH)2
find the moles of each reactant
moles=mass/molar mass
moles of CaO= 10 g/56 g/mol=0.179 moles
moles of H2O = 10 g/18 g/mol 0.556 moles
CaO is the limiting reagent therefore by use of mole ratio of CaO:Ca(OH)2 which is 1:1 moles of Ca(OH)2 is = 0.179 moles
mass= moles x molar mass
= 0.176 moles x 74 g/mol = 13.024 grams
Answer: The mass of an object is a measure of the object's inertial property, or the amount of matter it contains. Hope this is what your looking for.
Explanation:
True, H2O is a compound with 2 hydrogens and one oxygen
Answer:
Chloroform is expected to boil at 333 K (60 
).
Explanation:
For liquid-vapor equilibrium at 1 atm, 
= 0.
We know, 
, where T is temperature in kelvin scale.
Here both 
and 
are corresponding to vaporization process therefore T represents boiling point of chloroform.
So, ![0=(31.4\times 10^{3}\frac{J}{mol})-[T\times (94.2\frac{J}{mol.K})]](https://tex.z-dn.net/?f=0%3D%2831.4%5Ctimes%2010%5E%7B3%7D%5Cfrac%7BJ%7D%7Bmol%7D%29-%5BT%5Ctimes%20%2894.2%5Cfrac%7BJ%7D%7Bmol.K%7D%29%5D)
or, T = 333 K
So, at 333 K (60 ) , chloroform is expected to boil.
Answer:
- Dalton used creativity to modify Proust's experiment and interpret the results.
- Thomson used creativity to interpret the results of the cathode ray tube experiment.
Explanation:
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