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3 years ago

Describe two ways the material in this lesson

Chemistry

2 answers:

IgorLugansk [536]3 years ago

6 0

Answer:

- Dalton used creativity to modify Proust's experiment and interpret the results.

- Thomson used creativity to interpret the results of the cathode ray tube experiment.

Explanation:

give me brainlest

ohaa [14]3 years ago

4 0

Answer:

Dalton used creativity to modify Proust’s experiment and interpret the results.

Millikan used creativity to develop a way to measure the charge on an electron.

Thomson used creativity to interpret the results of the cathode ray tube experiment.

Rutherford used creativity to design an experiment to test the plum pudding model.

Explanation:

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7. The youngest part of the ocean floor is found ____.

aev [14]

Answer:

The answer is Near The Ocean Ridges.

5 0

2 years ago

Write the formula for the conjugate base for the following acids. Thank you

Llana [10]

Answer:

See the answer and explanation below , please.

Explanation:

A conjugate base is defined as that formed after an acid donates its proton.

For each article, a continuation of the conjugate bases (highlighted in bold), for dissociation in water:

a) HF + H20 --> F- + H30+

b) H20+ H20 --> OH- + H30+

C)H2PO3- + H20--> HPO3 2- + H30+

d) HSO4- + H20 --> SO4 2- + H30+

E) HCL02 + H20 --> CLO02 - + H30+

7 0

3 years ago

Read 2 more answers

What mass of precipitate forms when 185.5 ml of 0.533 m naoh is added to 627 ml of a solution that contains 15.8 g of aluminum s

Law Incorporation [45]

Answer:

2,57 g of precipitate.

Explanation:

For the reaction:

6 NaOH + Al₂(SO₄)₃ → 2 Al(OH)₃ + 3 Na₂SO₄

The precipitate is Al(OH)₃.

185,5mL of 0,533M NaOH are:

0,1855L × 0,533M = 0,0989 moles NaOH

Moles of Al₂(SO₄)₃ are:

15,8g × $\frac{1mol}{342,15g}$ = 0,0462 moles Al₂(SO₄)₃

For the total reaction of 0,0989 moles NaOH with Al₂(SO₄)₃ you need:

0,0989moles NaOH × $\frac{1molAl_{2}(SO_{4})_{3}}{6 moles NaOH}$ = 0,0165 moles Al₂(SO₄)₃

As you have 0,0462 moles Al₂(SO₄)₃ the limiting reactant is NaOH.

0,0989 moles of NaOH produce:

0,0989moles NaOH × $\frac{2molAl(OH)_{3}}{6 moles NaOH}$ = 0,0330 moles of Al(OH)₃

These moles are:

0,0330 moles of Al(OH)₃ × (78 g/mol) = 2,57 g of Al(OH)₃ ≡ mass of precipitate

I hope it helps!

3 0

3 years ago

Que es un cuerpo de materia

vaieri [72.5K]

Answer: 47586

Explanation:

Mhm

8 0

3 years ago

Can someone help with this???

e-lub [12.9K]

Answer:

2Mg(s) +O₂(g) → 2MgO(s)

Explanation:

Mg(s) +O₂(g) → MgO(s)

When a chemical equation is balanced, the number of atoms of each element is equal on both sides of the arrow. We usually balance O and H last.

In this case, the number of Mg atoms is equal on both sides. Thus, let's move on to balance the O atoms. On the left side, there are 2 O atoms, while there is only 1 O atom on the left side. Thus, write a '2' in front of MgO.

Mg(s) +O₂(g) → 2MgO(s)

Now, the number of Mg atoms is not equal. Write a '2' in front of Mg to balance it.

2Mg(s) +O₂(g) → 2MgO(s)

The equation is now balanced with 2 Mg atoms and 2 O atoms on each side.

6 0

3 years ago