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Alchen [17]
3 years ago
7

Find the angle measure of minor arc MP.

Mathematics
2 answers:
ella [17]3 years ago
5 0

Step-by-step explanation:

Angle at center = 2 * Angle at circumference.

Angle MNP = 2 * Angle MQP = 30°.

Hence the angle measure of minor arc MP is 30°.

Vaselesa [24]3 years ago
3 0

Answer:

30 degrees

Step-by-step explanation:

arc measure in degrees is twice the measure of the inscribed angle

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PLEASE HELP ME OUT
liubo4ka [24]

Answer:

18.84 ft

Step-by-step explanation:

The formula for the circumference of a circle is C = πd or C = 2πr

We will use C = 2πr since we have r given in the photo

  • We just need to substitute our values into the formula:
  • C = 2(3.14)(3) = 18.84 ft
8 0
3 years ago
Divide.<br> a.1 − 2i/2i<br> b. 5 − 2i/5 + 2i<br> c.√3 − 2i/−2 − √3i
Umnica [9.8K]

Answer:

(a) \frac{-1i}{2}-1[/tex]

(b) \frac{20i+21}{29}

(c) i

Step-by-step explanation:

We have to perform division

(a) \frac{1-2i}{2i}

So after division

\frac{1-2i}{2i}=\frac{1}{2i}-\frac{2i}{2i}=\frac{-1i}{2}-1

(b) We have given expression \frac{5-2i}{5+2i}

After rationalizing \frac{5-2i}{5+2i}\times \frac{5-2i}{5-2i}=\frac{(5-2i)^2}{25+4}=\frac{25+4i^2+20i}{29}=\frac{20i+21}{29}

(c) We have given expression \frac{\sqrt{3}-2i}{-2-\sqrt{3i}}

After rationalizing

\frac{\sqrt{3}-2i}{-2-\sqrt{3i}}\times \frac{-2+\sqrt{3i}}{-2+\sqrt{3i}}=\frac{-2\sqrt{3}+7i+2\sqrt{3}}{7}=\frac{7i}{7}=i

5 0
3 years ago
Will mark as brainliest if correct
Alenkinab [10]

Answer:

x = 2

Step-by-step explanation:

9^2 or 9(9) = 81

8 0
3 years ago
Let f(x) = |x| for all real numbers x. Write the formula for the function represented by the described
Ostrovityanka [42]

Answer:

y=(\frac{1}{3}f(x-3))-1

Step-by-step explanation:

Please see the picture below.

1. Given the function f(x) = |x|, applying a vertical stretch with scale factor \frac{1}{3}, we have the transformed function:

y=\frac{1}{3}f(x)

2. Applying a translation of 3 units to the right, we have:

y=\frac{1}{3}f(x-3)

3. Finally applying a translation down of 1 unit, we have:

y=(\frac{1}{3}f(x-3))-1

6 0
3 years ago
Determine whether the function f(x) = -9.5 + 6 + x² is even, odd or neither.
zimovet [89]

Answer:

The function f(x) = -9.5 + 6 + x² is neither odd or even.

Step-by-step explanation:

We know that a function is termed as 'even' when

f(-x) = f(x) for all x

We know that a function is termed as 'odd' when

f(-x) = -f(x) for all x

Given the function

f(x) = -9.5x⁵ + 6 + x²

substitute x with -x

f(-x) = -9.5(-x)⁵ + 6 + (-x)²

as (-x)⁵ = -x⁵, so

f(-x) = -(-9.5x)⁵ + 6 + (-x)²

Apply exponent rule: (-a)ⁿ = aⁿ, if n is even

f(-x) = -(-9.5x)⁵ + 6 + x²

Apply rule: -(-a) = a

f(-x) = 9x⁵ + 6 + x²

As

f(-x) ≠ f(x) ≠ -f(x)

Therefore, the function f(x) = -9.5 + 6 + x² is neither odd or even.

5 0
3 years ago
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