The correct answer of this question is : From high potential to low potential.
EXPLANATION :
Before going to answer this question, first we have to understand the conventional rule for current flow.
As per the conventional rule of electricity, the current direction is opposite to the direction of electronic motion.
The current flows through a conductor is due to the motion of the free electrons. When the conductor or wire is attached to any electric source, the electrons are drifted towards the positive terminal of the source. Hence, electrons are moving from negative terminal to positive terminal.
As per the conventional rule, the current direction will be from positive terminal towards negative terminal i.e from higher potential to lower potential.
Hence, the correct answer of this question is from higher potential to lower potential .
Answer:
El avión recorrió 45 km en los 180 s.
Explanation:
La relación entre velocidad, distancia y tiempo se da de la siguiente manera;
![Velocidad= \dfrac{Distancia}{Hora}](https://tex.z-dn.net/?f=Velocidad%3D%20%5Cdfrac%7BDistancia%7D%7BHora%7D)
Por lo cual los parámetros dados son los siguientes;
Velocidad = 900 km/h = 250 m / s
Tiempo = 180 s
Estamos obligados a calcular la distancia recorrida
De la ecuación para la velocidad dada arriba, tenemos;
Distancia recorrida = Velocidad pf viaje × Tiempo de viaje
Distancia recorrida = 900 km/h × 180 s = 900
Distancia recorrida = 900 km/h × 1 h/60 min × 1 min/60 s × 180 s = 45 km
Por lo tanto, el avión viajó 45 km en 180 s.
Answer: I’m gonna assume 40 m north
The velocity of an object is the rate of change of its position with respect to a frame of reference, and is a function of time. Velocity is equivalent to a specification of an object's speed and direction of motion (e.g. 60 km/h to the north).
Answer:
![Imp = 5626.488\,\frac{kg\cdot m}{s}](https://tex.z-dn.net/?f=Imp%20%3D%205626.488%5C%2C%5Cfrac%7Bkg%5Ccdot%20m%7D%7Bs%7D)
Explanation:
First, it is required to model the function that models the increasing force in the +x direction:
![a =\frac{781..25\,N}{(1.27\,s)^{2}}](https://tex.z-dn.net/?f=a%20%3D%5Cfrac%7B781..25%5C%2CN%7D%7B%281.27%5C%2Cs%29%5E%7B2%7D%7D)
![a = 484 \frac{N}{s^{2}}](https://tex.z-dn.net/?f=a%20%3D%20484%20%5Cfrac%7BN%7D%7Bs%5E%7B2%7D%7D)
The equation is:
![F_{x} = 484\,\frac{N}{s^{2}}\cdot t^{2}](https://tex.z-dn.net/?f=F_%7Bx%7D%20%3D%20484%5C%2C%5Cfrac%7BN%7D%7Bs%5E%7B2%7D%7D%5Ccdot%20t%5E%7B2%7D)
The impulse done by the engine is given by the following integral:
![Imp=484\,\frac{N}{s^{2}} \int\limits^{3.50\,s}_{2\,s} {t^{2}} \, dt](https://tex.z-dn.net/?f=Imp%3D484%5C%2C%5Cfrac%7BN%7D%7Bs%5E%7B2%7D%7D%20%5Cint%5Climits%5E%7B3.50%5C%2Cs%7D_%7B2%5C%2Cs%7D%20%7Bt%5E%7B2%7D%7D%20%5C%2C%20dt)
![Imp = 161.333\,\frac{N}{s^{2}}\cdot [(3.50\,s)^{3}-(2\,s)^{3}]](https://tex.z-dn.net/?f=Imp%20%3D%20161.333%5C%2C%5Cfrac%7BN%7D%7Bs%5E%7B2%7D%7D%5Ccdot%20%5B%283.50%5C%2Cs%29%5E%7B3%7D-%282%5C%2Cs%29%5E%7B3%7D%5D)
![Imp = 5626.488\,\frac{kg\cdot m}{s}](https://tex.z-dn.net/?f=Imp%20%3D%205626.488%5C%2C%5Cfrac%7Bkg%5Ccdot%20m%7D%7Bs%7D)