Answer:
1.0 *10^(-4) mol
Explanation:
For gases:
n1/n2 = V1/V2
n1/3.8*10^(-4) mol = 230 mL/ 860 mL
n1 = 3.8*10^(-4)*230/860 = 1.0 *10^(-4) mol
Solution:
a) By stoichoimetry If 6 moles of gives 4 mole of , then 22 moles of will give: moles of
b) If 6 moles of reacts with one mole of , then 22 moles of will react : moles of
Moles of left after the reaction = moles.
c) 0 Moles of , since it is present in less amount it will get completely consumed in the reaction. Hence, it is limiting reagent.
8.092752363 ×10 to the power of 22