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REY [17]
1 year ago
5

How much did shell erosion increase between 1995 and 2020?

Chemistry
1 answer:
saveliy_v [14]1 year ago
5 0

The mussel shell erosion increased by 30 percent points between 1995 and 2020.

<h3>What is erosion?</h3>

Erosion is the washing away of the top layer of a substance or material.

The mussel shell erosion is a type of erosion which occurs in mussel shell as a results of chemical changes that occur on their environment.

The mussel shell erosion is shown on the graph.

Therefore, based on the graph, mussel shell erosion increased by 30 percent points between 1995 and 2020.

Learn more about erosion at: brainly.com/question/12759847

#SPJ1

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Help plz:)))I’ll mark u Brainliest
4vir4ik [10]
Matter is anything that has mass and occupies space, It can exist in 3 states, or phases: solid, liquid, and gas.

Solid molecules are closely packed together and retain a fixed shape.

Liquid molecules aren't packed very closely, and take the shape of the bottom of the container.

Gas molecules are far apart and fill the container

completely.
7 0
2 years ago
Read 2 more answers
What do the elements in each pair have in common? k, kr be, mg ni, tc b, ge al, pb?
tensa zangetsu [6.8K]
The pairs are:
K, Kr - Same period
Be, Mg - Same group
Ni, Tc - Both are transition metals
B, Ge - Both are metaloids
Al, Pb - Both form inert oxides
4 0
3 years ago
...............………...mkmlkml;m
bagirrra123 [75]

Answer:

390

Explanation:

Specific heat capacity= heat/mass × temperature

x = 2925 \div 0.5 \times 15 = 390

Remember you convert gram into kilogram and 1 gram =0.001 kilogram

5 0
2 years ago
How are the various features of the Earth created by the Earth’s inner processes?
goblinko [34]

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8 0
3 years ago
9. Using the balanced equation from Question #8, how many grams of lead will be produced if 2.54 grams of PbS is burned with 1.8
MissTica

Answer: 2.24 grams of Pb

Explanation:

<u>Step 1</u>

Balanced chemical reaction;

2PbS + 3O2 → 2Pb + 2SO3

<u>Step 2</u>

Moles of both PbS and O2

Moles = mass / molar mass

Moles of PbS = 2.54 g / 239.3 g/mol = 0.0108 moles

Moles of O2 = 1.88 / 32 g/mol = 0.0588 moles

<u>Step 3</u>

Finding the limiting reactant.

Limiting reactant, is that reactant which is completely used in the reaction;

If we assume that PbS is the limiting reactant;

We have 0.0588 moles of O2. This needs ( 0.0588 * 2) / 3 = 0.0392 moles of PbS to fully react. But we have only 0.0108 moles of PbS available. That means that the PbS will be completely consumed hence the limiting reactant

If we assume O2 is the limiting reactant;

We have 0.0108 moles of PbS. That needs ( 0.0108 * 3) / 2 = 0.0162 moles of O2. But we have 0.0588 moles of O2 which is in excess further confirming that PbS is the limiting reactant since it will be depleted in the reaction.

<u>Step 4</u>

Moles of lead

For this step we apply the mole ratios with the limiting reactant;

Mole ratio of PbS : Pb = 2 : 2 = 1 : 1

Therefore;

Moles of Pb = (0.0108 moles  * 1 ) 1

Moles of Pb =0.0108 moles

<u>Step 5</u>

Mass of Pb

Mass = moles * molar mass

Mass of Pb =0.0108 moles * 207.2 g/mol

Mass of Pb = 2.24 grams

5 0
2 years ago
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