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2 years ago

What is the percent composition of (NH4)2S?

Chemistry

1 answer:

enyata [817]2 years ago

3 0

(NH₄)₂S

%N= 41.18%

%H =11.76%

%S=47.06%

Mg(NO₃)₂

%Mg=32.43%

%N=18.92%

%O=(64.86%

<h3>Further explanation</h3>

Given

(NH₄)₂S

Mg(NO₃)₂

Required

The percent composition

Solution

(NH₄)₂S MW=68 g/mol

%N=2. Ar N / MW (NH₄)₂S x 100%

%N= (2.14/68) x 100% = 41.18%

%H =(8.1/68) x 100%=11.76%

%S=(32/68)x 100%=47.06%

Mg(NO₃)₂ MW=148 g/mol

%Mg=(2.24/148)x100%=32.43%

%N=(2.14/148)x100%=18.92%

%O=(6.16/148)x100%=64.86%

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tensa zangetsu [6.8K]

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Putting in the values we get:

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3 years ago

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aleksandrvk [35]

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2 years ago

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