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morpeh [17]
3 years ago
5

Show with proof, the planet which an astronaut would have a greater weight if Planet A has twice the mass and twice the radius o

f Planet B.
Physics
1 answer:
meriva3 years ago
4 0

Answer:

First let's look at the gravitational formula by newton:

f = g \times  \frac{m1 \times m2}{ {r}^{2} }

Now the f and g should be capital but that's not possible with the equation system. But we can see that the force the astronaut is pulled at is dependent on the mass and the distance if we assume his mass stays the same (mass and weight aren't the same also g is a constant). If a planet has twice the radius the force will by four times as weak because of the ^2. This is not compensated by the twice as big mass. Therefore the astronaut will have a higher force and thus a higher weight on planet B

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New alleles arising from mutations in a population will​
ivanzaharov [21]
Increase in frequency over time until they reach fixation, replacing the ancestral allele in the population
8 0
3 years ago
A Carnot engine operates between temperature levels of 600 K and 300 K. It drives a Carnot refrigerator, which provides cooling
KATRIN_1 [288]

Explanation:

Formula for maximum efficiency of a Carnot refrigerator is as follows.

      \frac{W}{Q_{H_{1}}} = \frac{T_{H_{1}} - T_{C_{1}}}{T_{H_{1}}} ..... (1)

And, formula for maximum efficiency of Carnot refrigerator is as follows.

     \frac{W}{Q_{C_{2}}} = \frac{T_{H_{2}} - T_{C_{2}}}{T_{C_{2}}} ...... (2)

Now, equating both equations (1) and (2) as follows.

 Q_{C_{2}} \frac{T_{H_{2}} - T_{C_{2}}}{T_{C_{2}}} = Q_{H_{1}} \frac{T_{H_{1}} - T_{C_{1}}}{T_{H_{1}}}        

        \gamma = \frac{Q_{C_{2}}}{Q_{H_{1}}}

                    = \frac{T_{C_{2}}}{T_{H_{1}}} (\frac{T_{H_{1}} - T_{C_{1}}}{T_{H_{2}} - T_{C_{2}}})

                    = \frac{250}{600} (\frac{(600 - 300)K}{300 K - 250 K})

                    = 2.5

Thus, we can conclude that the ratio of heat extracted by the refrigerator ("cooling load") to the heat delivered to the engine ("heating load") is 2.5.

4 0
3 years ago
Two skaters, one with mass 75 kg and the other with mass 60 kg, stand on an ice rink holding a pole of length 14 m and negligibl
Bumek [7]

Answer: 70m

Explanation:

Given, 2 skaters, one with a mass of 60kg.

Another 75kg.

Distance is 14m.

Assuming the system centre if mass does not change, both skaters would meet at the centre of the mass

let the 60kg skater be xm away from the centre, then, the 75kg skater would be (14 - x)m away from the centre too

m1x + m2(14 - x) = 0

m1x + 14m2 - m2x = 0

60x + 14*75 - 75x = 0

60x - 75x + 1050 = 0

-15x + 1050 = 0

15x = 1050

x = 70

Thus, the distance the 65kg skater moves is 70m

7 0
3 years ago
Read 2 more answers
A hunter is practicing hitting a target that is down range. If the arrow leaves the bow at a velocity of 30ms at an angle of 40°
Flauer [41]

Answer:

Explanation:

range of projectile = u² sin2θ / g

u = 30 m /s

θ = 40°

range = 30² x sin 80 / 9.8

= 90.44 m

b )

maximum altitude H = u² sin²θ / 2 x g

= 30² sin²40 / 9.8

= 37.94 m .

6 0
3 years ago
An object starts moving at 10 ms and has an acceleration of 2 ms-2. Find its speed after 5 seconds
Westkost [7]

Answer:

speed =15m/s

distance =75m

8 0
3 years ago
Read 2 more answers
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