5 g of potassium oxalate react to produce 0.03 moles of calcium oxalate.
Calcium oxalate (CaC₂O₄) is obtained by the reaction of 5 g of potassium oxalate (K₂C₂O₄).
We can calculate the moles of CaC₂O₄ obtained considering the following relationships.
- The molar mass of K₂C₂O₄ is 184.24 g/mol.
- The mole ratio of K₂C₂O₄ to CaC₂O₄ is 2:1.
5 g of potassium oxalate react to produce 0.03 moles of calcium oxalate.
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Answer:
Ionic compounds generally form between elements that are metals and elements that are nonmetals. For example, the metal calcium (Ca) and the nonmetal chlorine (Cl) form the ionic compound calcium chloride (CaCl2). In this compound, there are two negative chloride ions for each positive calcium ion
Answer:
10 Kilograms
Explanation:
"millimetres" is a unit of measurement and is used for measuring distances.
"newton" is a unit of weight and is used to represent the weight of an object
:kilograms" is the one used for measuring mass
It can be predicted from the location on the periodic table.
The enthalpy of this reaction is -296. 8 kJ/mol.
The equation of the reaction is;
S(s) + O2(g) -----> SO2(g)
Recall that the enthalpy of the reaction can be obtained from the formula;
ΔHrxn = ΔHf(products) - ΔHf(reactants)
We know that;
ΔHf S(s) = 0 KJ/mol
ΔHf O2(g) = 0 KJ/mol
ΔHf SO2(g) = -296. 8 kJ/mol
Hence;
ΔHrxn = -296. 8 kJ/mol - [0 KJ/mol + 0 KJ/mol]
ΔHrxn = -296. 8 kJ/mol
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