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ivanzaharov [21]
3 years ago
8

Formula of a substance in water is followed by what symbol

Chemistry
1 answer:
snow_lady [41]3 years ago
8 0
The substance is followed by H2O
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The table above this place up icicle properties of a diamond by the property names have been left out of the top row which prope
Vika [28.1K]

Answer:

icicle becausit sounds right

Explanation:

icicles because it sounds right

8 0
3 years ago
What pressure, in atm, would be exerted by 0.023 grams of oxygen (O2) if it occupies 31.6 mL at 91
Vikentia [17]

Answer:  A pressure of 0.681 atm would be exerted by 0.023 grams of oxygen (O_2) if it occupies 31.6 mL at 91^{o}C.

Explanation:

Given : Mass of oxygen = 0.023 g

Volume = 31.6 mL

Convert mL into L as follows.

1 mL = 0.001 L\\31.6 mL = 31.6 mL \times \frac{0.001 L}{1 mL}\\= 0.0316 L

Temperature = 91^{o}C = (91 + 273) K = 364 K

As molar mass of O_2 is 32 g/mol. Hence, the number of moles of O_2 are calculated as follows.

No. of moles = \frac{mass}{molar mass}\\= \frac{0.023 g}{32 g/mol}\\= 0.00072 mol

Using the ideal gas equation calculate the pressure exerted by given gas as follows.

PV = nRT

where,

P = pressure

V = volume

n = number of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the value into above formula as follows.

PV = nRT\\P  \times 0.0316 L = 0.00072 mol \times 0.0821 L atm/mol K \times 364 K\\P = \frac{0.00072 mol \times 0.0821 L atm/mol K \times 364 K}{0.0316 L}\\= 0.681 atm

Thus, we can conclude that a pressure of 0.681 atm would be exerted by 0.023 grams of oxygen (O_2) if it occupies 31.6 mL at 91^{o}C.

4 0
3 years ago
Balance this equation. Not all spots have to have a number.
Lisa [10]

2Na+2H2O----2NaOH+H2

3 0
3 years ago
What kind of reaction is AgNO3+KI —> AgI+KNO3?
Scilla [17]

Answer:

Substitution reaction

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3 years ago
An element is to a __ as an organ is to a ___
Vera_Pavlovna [14]

Answer:

An element is to a compound as an organ is to tissue

Explanation:

5 0
3 years ago
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