First you need to find the balanced chemical formula.
CuCl₂+2NaNO₃→2NaCl+Cu(NO₃)₂
Then you can find out how much NaCl 31.0g of CuCl₂ should produce using stoichiometry. Divide 31.0g by the molar mass of CuCl₂ (134.446g/mol) to get 0.2306mol CuCl₂. Than multiply 0.2306mol CuCl₂ by 2 to get 0.4612mol NaCl. Than multiply 0.4612mol by the molar mass of NaCl (58.45g/mol) to get 26.95g of NaCl.
that means that 100% yield would give you 26.95g of NaCl so to find percent yield divide 21.2 by 26.95 to get 0.7867 which is 78.7% yield
Therefore the answer is 78.7% yield.
I hope this helps. Let me know if anything is unclear
Answer:
Option B, Al --> Al3+ + 3e-
Explanation:
Oxidation is defined as the process of losing electron by a molecule, atom or anion thereby acquiring oxidation state i.e the positive charge. Reduction on the other hand is the process in which an atom, ion or molecule gains electron and gains negative charge on it.
For example – In the reaction, H2 + F2 → 2 HF, hydrogen is oxidized H2 → 2 H+ + 2 e- as it looses electron while fluorine is being reduced F2 + 2 e- → 2 F-
This is happening in the option B
Percentage yield= (actual/theoretical)x100
So in this case the actual yield is 110 and the theoretical yield is 125.
So you would do =(110/125)x100
So the answer would be =88%
