Answer:
Explanation:
Hello,
In this case we use the Boyle's law which allows us to understand the volume-pressure behavior as an inversely proportional relationship:
Whereas we solve for 
as the required final pressure:
Best regards.
Answer:
I think it is three times I'm not sure
Answer:
in general, as the temperature increases, the solubility of gases in water <u>decreases</u> and the solubility of most solids in water <u>increases</u>.
Answer:
Q = 2640.96 J
Explanation:
Given data:
Mass of He gas = 10.7 g
Initial temperature = 22.1°C
Final temperature = 39.4°C
Heat absorbed = ?
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree. Specific heat capacity of He is 14.267 J/g.°C
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 39.4°C - 22.1°C
ΔT = 17.3°C
Q = 10.7 g× 14.267 J/g.°C × 17.3°C
Q = 2640.96 J
