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adell [148]
4 years ago
9

What do ionic compounds form

Chemistry
1 answer:
Snowcat [4.5K]4 years ago
3 0

Answer:

By the result of the formation of positive and negative ions, Ionic compounds are formed.

Explanation:

Electrons are actually transferred from one atom to another to form rare gas electron structures for each ion. The atom which forms a positive ion loses electrons to the atom which gains electrons to form a negative ion. A compound is not stable unless the number of electrons which are lost and gained are equal

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What is the name of MnO? Explain how you determined the bond type and the steps you used to determine the naming convention for
xeze [42]

Answer:

Magnesiumoxide

Explanation:

I don't know

5 0
3 years ago
Which of the following equations does not demonstrate the law of conservation of mass?
enot [183]

The third option does not obey the law of conservation of mass.

Option 3.

Explanation:

The law of conservation of mass states that the sum of the masses of reactants should be equal to the sum of the masses of the products.

For example, if we consider the first option to verify if it obeys law of conservation of mass or not, 2 Na + Cl₂ → 2 NaCl

So one way to verify it is to find the mass of Na, then multiply it with 2, and then add this with 2 times of mass of chlorine. So this sum should be equal to the 2 times mass of NaCl. But it is somewhat lengthy.

Another way to easily determine this is to check if the elements are present equally in both sides. Such as, in reactant side and product side 2 atoms of Na is present . Similarly, the Cl atoms are also present in equal number in both reactant and product side. Thus this obeyed the law of conservation of mass.

Like this, if we see the second option, there also 1 atom of Na is present in reactant and product side and 2 molecules of H is present in reactant and product side, 1 oxygen is present in reactant and product side and 1 Cl is present in reactant and product side. So it also obeys the law of conservation of mass.

But in the third option, P₄ + 5 O₂→ 2 P₄O₁₀, here, there is 4 atoms of P in reactant side but in product side there is (4*2) = 8 atoms of P. Similarly, the number of atoms of oxygen in reactants and product side is also not same. So the third option does not obey the law of conservation of mass.

The fourth option also obeys the law of conservation of mass as the number of atoms of each element is same in both the product and reactant side.

Thus, the third option does not obey the law of conservation of mass.

5 0
3 years ago
Hi can someone help me answer this!
Arada [10]
the answer to this question is B.
7 0
3 years ago
What is the overall reaction order for this rate law: rate= k[A][B]?
nika2105 [10]
The over all order of the reaction with the rate law of rate=k[A][B] is 2 since the exponent for [A] is 1 and the exponent for [B] is 1 and 1+1=2.  

for example the order for the rate law rate=[A]²[B] is 3 since 2+1=3 and the order for a rate law of rate=[A]²[B]³ the order would be 5 since 2+3=5.

I hope this helps.  Let me know if anything is unclear.
5 0
3 years ago
The vapor pressure of pure ethanol at 60 °c is 0.459 atm. raoult's law predicts that asolution prepared by dissolving 10.0 mmol
Vlad1618 [11]
Raoult's law is stated as<span> the partial </span>vapor pressure<span> of each component in the </span> mixture<span> of ideal liquids is equal to the vapor pressure of the pure component multiplied by its </span>mole fraction<span> in the mixture. Mathematically, it is expressed as

P = Xi Pi

where P= vapor  pressure of solution
Xi = mole fraction of i component
Pi = vapor pressure of pure i component.

In present case, P1 = 0.459 atm and n1 = number of mole  of ethanol = 0.090
n2 = number of mole of </span><span> naphthalene = 0.01

</span>∴ Mole fraction of ethanol = \frac{n1}{\text{n1 + n2}} = \frac{0.090}{\text{0.090 + 0.010}}  = 0.9

Thus, vapor pressure of solution = 0.9 X 0.459 = 0.4131 atm. 

Answer: <span>The vapor pressure of pure ethanol at 60 °c is 0.459 atm. Raoult's law predicts that a solution prepared by dissolving 10.0 mmol naphthalene (nonvolatile) in 90.0 mmol ethanol will have a vapor pressure of 0.4131 atm.</span>
6 0
3 years ago
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