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galina1969 [7]
3 years ago
13

Which statement best describes the density of an atom's nucleus?​

Chemistry
1 answer:
malfutka [58]3 years ago
7 0

Answer:

Very small

Explanation:

Simply science

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Wat two common uses for Gallium??
Ann [662]

Answer:

mirrors and metal thermometers

Explanation:

ooga booga

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3 years ago
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What is the electron configuration for the Magnesium ion?​
soldi70 [24.7K]
1s^2 2s^2 2p^6 for the Mg2+ ion.
4 0
2 years ago
How many molecules of carbon dioxide are in 9.080 x 10 ^-1 mol?
kakasveta [241]

Answer:

5.46 8 x 10²³ molecules.

Explanation:

  • <em>Knowing that every one mole of a substance contains Avogadro's no. of molecules (NA = 6.022 x 10²³).</em>

<em><u>Using cross multiplication:</u></em>

1.0 mole → 6.022 x 10²³ molecules.

9.08 x 10⁻¹ mole → ??? molecules.

∴ The no. of molecules of CO₂ are in 9.08 x 10⁻¹ mol = (6.022 x 10²³ molecules) ( 9.08 x 10⁻¹ mole) / (1.0 mol) = 5.46 8 x 10²³ molecules.

6 0
3 years ago
1.) What are the two broad categories that elements can be divided into?
hoa [83]

Answer:

1) Metals and nonmentals

2) Elements: Oxygen (O_{2} \\) , Nitrogen (N_{2}

3) Compounds: Carbon Dioxide CO_{2}, Methane CH_{4}, Nitrogen DioxideNO_{2}

Explanation:

5 0
3 years ago
How many bromine atoms are present in 37.9 g of CH2Br2?
VARVARA [1.3K]

Answer:

The answer to your question is: 6.55 x 10 ²³ atoms of Br

Explanation:

CH2Br2 = 37.9 g

MW CH2Br2 = (12 x 1) + (2 x 1) + (80 x 2) = 174 g

                   174 g of CH2Br2 ------------------  160 g of Br2

                   37.9 g of CH2Br2   ---------------     x

                x = 37.9 x 160/174 = 34.85 g of Br

                      1 mol of Br -----------------   160 g Br2

                         x              ----------------    174 g Be2

               x = 174 x 1 /160 = 1.088 mol of Br2

                1 mol of Br -----------------  6.023 x 10 ²³ atoms

            1.088 mol of Br -------------    x

                    x = 1.088 x 6.023 x 10 ²³ / 1 = 6.55 x 10 ²³ atoms

4 0
3 years ago
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