Find the mass of C in the 2.657 g CO2: (2.657 g CO2) / (44.01 g/mol) = 0.06037 mol CO2 Since each mole of CO2 also has 1 mole of C, this is equivalent to 0.06037 mol C.
Find the mass of H in the 1.089 g H2O: (1.089 g H2O) / (18.02 g/mol) = 0.06043 mol H2O Since 1 mol H2O has 2 mol H, this is equivalent to (0.06043)*2 = 0.1209 mol H.
Taking the ratio of H to C: 0.1209 / 0.06037 = 2.002 ~ 2 Therefore, the empirical formula of isobutylene is CH2.