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ryzh [129]
2 years ago
8

Isobutylene is a hydrocarbon used in the manufacture of synthetic rubber. when 0.847 g of isobutylene was subjected to combustio

n analysis, the gain in mass of the co2 absorber was 2.657 g and that of the h2o absorber was 1.089 g. what is the empirical formula of isobutylene?
Chemistry
1 answer:
Firlakuza [10]2 years ago
6 0
Find the mass of C in the 2.657 g CO2:
(2.657 g CO2) / (44.01 g/mol) = 0.06037 mol CO2
Since each mole of CO2 also has 1 mole of C, this is equivalent to 0.06037 mol C.

Find the mass of H in the 1.089 g H2O:
(1.089 g H2O) / (18.02 g/mol) = 0.06043 mol H2O
Since 1 mol H2O has 2 mol H, this is equivalent to (0.06043)*2 = 0.1209 mol H.

Taking the ratio of H to C: 0.1209 / 0.06037 = 2.002 ~ 2
Therefore, the empirical formula of isobutylene is CH2.
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Bi2(CO3)3<br> Name of this compound
Keith_Richards [23]

Answer:

The name of this compound is :

Bi2(CO3)3 = Bismuth Carbonate

Explanation:

The name of the compound is derived from the name of the elements present  in it.

The rule followed while naming the compound are:

1. The first element (always the cation) is named as such .

2. The second element (The anion) end with "-ate ,  -ide ," etc

3. NO prefix is added while naming the first element.

For example : Bi2 can't be named as Dibismuth

Na2 = Can't be named as disodium

Hence the compound :

Bi2(CO3)3 contain two element : Bi and CO3. Here , Bi = cation (named as such) and CO3 = anion (named according to rules)

Bi = Bismuth

CO3 = carbonate

Bi2(CO3)3 = Bismuth Carbonate

The molecular mass of this compound is :

Molecular mass = 2 (mass of Bi) + 3(mass of C) + 6(mass of O)

= 2 (208.98)+3(12.01)+6(15.99)

= 597.987 u

5 0
3 years ago
solve the following and express your answer in the correct number of significant figures 9.11 × 10∧-11 ÷ 6.02 × 10∧23
Greeley [361]
I got 1.513289037E12
8 0
2 years ago
Which of the following equations follows the law of conservation of mass?
Dovator [93]

Answer:

option A = C₂H₄ + 3O₂   →    2CO₂   +  2H₂O

Explanation:

Law of conservation of mass:

This law stated that mass can not be created or destroyed in chemical reaction. It just changed from one to another form.

For example:

C₂H₄   +   3O₂   →    2CO₂   +  2H₂O

28 g   + 96 g    =      88 g  +  36 g

    124  g           =      124 g

This reaction correctly hold the law of conservation of mass.

Other options:

C  + 4H₂  →   CH₄

12 g  + 8g  = 16 g

  20 g  =   16 g

This reaction do not hold the law of conservation of mass.

3H₂O  →   3H₂  +  3O₂

  54 g  =   6 g +  96 g

   54 g =   102 g

This reaction do not hold the law of conservation of mass.

2Na  +  Cl  →  NaCl

46 g  + 35.5 g  =   58.5 g

  81.5 g = 58.5 g

This reaction do not hold the law of conservation of mass.

6 0
3 years ago
Read 2 more answers
Complete the equation determine if there are precipitates write the balanced ionic and net ionic equations. If there is no preci
alukav5142 [94]

You may find bellow the balanced chemical equations.

Explanation:

Molecular equations:

3 Sr(NO₃)₂ (aq) + 2 K₃PO₄ (aq) → Sr₃(PO₄)₂ (s) + 6 KNO₃ (aq)

2 NaOH (aq) + Ni(NO₃)₂ (aq) = Ni(OH)₂ (s) + 2 NaNO₃ (aq)

Ionic equations:

3 Sr²⁺ (aq) + 6 NO₃⁻ (aq) + 6 K⁺ (aq) + 2 PO₄³⁻ (aq) →  Sr₃(PO₄)₂ (s) + 6 K⁺ (aq) + 6 NO₃⁻ (aq)

2 Na⁺ (aq) + 2 OH⁻ (aq) + Ni²⁺ (aq) + 2 NO₃⁻ (aq) = Ni(OH)₂ (s) + 2 Na⁺ (aq) + 2 NO₃⁻ (aq)

To get the net ionic equation we remove the spectator ions:

3 Sr²⁺ (aq) + 2 PO₄³⁻ (aq) →  Sr₃(PO₄)₂ (s)

2 OH⁻ (aq) + Ni²⁺ (aq) = Ni(OH)₂ (s)

Learn more about:

net ionic equations

brainly.com/question/7018960

#learnwithBrainly

4 0
3 years ago
12. Aditya is stacking some cups. The diagram above shows the cups before they touch each other. Use the information in the diag
Pepsi [2]
Aditya would be the cooler person in this situation I think idk
8 0
3 years ago
Read 2 more answers
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