25 = -16t^2 + 50t + 4
16t^2 - 50t + 21 = 0
16t^2 - 8t - 42t + 21 = 0
8t(2t - 1) - 21(2t - 1) = 0
(8t - 21)(2t - 1) = 0
8t - 21 = 0 or 2t - 1 = 0
t = 21/8 or t = 1/2
t = 2.625 or t = 0.5
Answer: the simplified expression is
2y^15/(3x^5z^12)
Step-by-step explanation:
The given expression is
(-8x^2y^8z^-5) / (12^4y^-7z^7)
To simplify the given expression, we would apply one of the rules of indices. It is expressed as follows
x^a ÷ x^b = x^(a - b)
Applying the above rule of indices, the expression becomes
(-8/12 × x^(2 - 7) × y^(8 - - 7) × z^ (- 5 - 7)
= - 2/3 × x^- 5 × y^15 × z^-12
= - 2/3x^- 5y^15z^-12
= 2y^15/(3x^5z^12)
Your slope is -3 and your y intercept is 10
Complete Question:
sierrac3000
06/28/2019
Select the correct answer from each drop-down menu.
Samuel received $250 as prize money for winning the St. Peterson High School Badminton Tournament. The money was deposited in a special scholarship account that offered an annual interest of 1.8% compounded semiannually. The amount he will have in the account after t years can be calculated using the expression below.
250(1+0.018/2)^2t
Use the given expression to complete the statements below.
The expression is the *blank* of the amount initially deposited and the *blank* of one and the rate of increase raised to the number of *blank*
1st Blank:
Product
Sum
Quotient
Square
2nd Blank:
Quotient
Product
Difference
Sum
3rd Blank:
Compounding Periods
Years
Months
Answer:
1st blank = product
2nd blank = sum
3rd blank = years
Step-by-step explanation:
The expression given above is :
250(1+0.018/2)^2t
The expression can thus be explained as:
The *product* of the amount initially deposited and the *sum* of one and the rate of increase raised to the number of *years*
