What is the relevant similarity of the following argument?

A grocery shopper tosses a(n) 9.0 kg bag of rice into a stationary 17.4 kg grocery cart. The bag hits the cart with a horizontal

noname [10]

Answer:

$V=1.77m/s$

Explanation:

#Using the conservation of momentum , momentum before equals momentum after( $p=mv)$ .

-Initial speed is 5.2m/s while the cart is at rest. After, the velocity will be of a combined(bag+cart) mass.

Hence:

$9.0\times 5.2+17.4\times 0=(9+17.4)V\\\\V=\frac{9\times5.2}{9+17.4}\\\\=1.77m/s\\$

Hence, the final velocity of the cart and bag is 1.77m/s

7 0

4 years ago

Write the untis of following physical quantities electric current , force, frequency, density

Shtirlitz [24]

Answer:

1) electric current - ampere

2) force - joule

3 frequency - hertz

4) density - kilogram per cubic metre

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4 0

3 years ago

Read 2 more answers

A person standing 1.20 m from a portable speaker hears its sound at an intensity of 5.50 ✕ 10−3 W/m2. HINT (a) Find the correspo

iris [78.8K]

Answer:

PART A)

L = 97.4 dB

PART B)

$I = 6.11 \times 10^{-6} W/m^2$

PART C)

L = 67.9 dB

Explanation:

PART A)

level of sound is given as

$L = 10 Log\frac{I}{I_o}$

now we have

$L = 10 Log\frac{5.50\times 10^{-3}}{10^{-12}}$

$L = 97.4 dB$

PART B)

Since source is a spherical source

so here the intensity of sound is inversely depends on the square of the distance from the source

$\frac{I_2}{I_1} = \frac{r_1^2}{r_2^2}$

$\frac{I_2}{5.50 \times 10^-3} = \frac{1.20^2}{36^2}$

$I_2 = 6.11 \times 10^{-6} W/m^2$

PART C)

level of sound is given as

$L = 10 Log\frac{I}{I_o}$

now we have

$L = 10 Log\frac{6.11\times 10^{-6}}{10^{-12}}$

$L = 67.9 dB$

3 0

3 years ago

A fission reaction is one in which the weaker electrostatic repulsion force wins out over the ___________ nuclear force and, as

natulia [17]

The answer is b. Strong

6 0

4 years ago

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A pressure vessel that has a volume of 10m3 is used to store high-pressure air for operating a supersonic wind tunnel. If the ai

Anna71 [15]

Answer:

The mass of air stored in the vessel is 235.34 kilograms.

Explanation:

Let supossed that air inside pressure vessel is an ideal gas, The density of the air ( $\rho$ ), measured in kilograms per cubic meter, is defined by following equation:

$\rho = \frac{P\cdot M}{R_{u}\cdot T}$ (1)

Where:

$P$ - Pressure, measured in kilopascals.

$M$ - Molar mass, measured in kilomoles per kilogram.

$R_{u}$ - Ideal gas constant, measured in kilopascal-cubic meters per kilomole-Kelvin.

$T$ - Temperature, measured in Kelvin.

If we know that $P = 2026.5\,kPa$ , $M = 28.965\,\frac{kg}{kmol}$ , $R_{u} = 8.314\,\frac{kPa\cdot m^{2}}{kmol\cdot K}$ and $T = 300\,K$ , then the density of air is: