A certain unfiltered full-wave rectifier with 120 V, 60 Hz input produces an output with a peak of 15 V. When a capacitor-input
1 answer:
Answer:
The peak-to-peak ripple voltage = 2V
Explanation:
120V and 60 Hz is the input of an unfiltered full-wave rectifier
Peak value of output voltage = 15V
load connected = 1.0kV
dc output voltage = 14V
dc value of the output voltage of capacitor-input filter
where
V(dc value of output voltage) represent V₀
V(peak value of output voltage) represent V₁
V₀ = 1 - ( )V₁
make C the subject of formula
V₀/V₁ = 1 - (1 / 2fRC)
1 / 2fRC = 1 - (v₀/V₁)
C = 2fR ((1 - (v₀/V₁))⁻¹
Substitute for,
f = 240Hz , R = 1.0Ω, V₀ = 14V , V₁ = 15V
C = 2 * 240 * 1 (( 1 - (14/15))⁻¹
C = 62.2μf
The peak-to-peak ripple voltage
= (1 / fRC)V₁
= 1 / ( (120 * 1 * 62.2) )15V
= 2V
The peak-to-peak ripple voltage = 2V
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By using Lami's theorem formula, the tension in the supporting wires is 48.6 Newtons
TENSION
- Tension is also a force having Newton as S.I unit.
- The tension in the wire will be the same.
This question can be solved by using either vector diagram or by using Lami's theorem.
The sum of two given angles = 42 + 42 = 84 degrees
The third angle = 180 - 84 = 96 degrees.
Below is the Lami's theorem formula
Where
= 42 + 90 = 132 degrees
Y = 96 degrees
W = 65 N
By using the formula, we have
T/sin 132 = 65/sin96
Cross multiply
T = 0.743 x 65.57
T = 48.56 N
Therefore, the tension in the supporting wires is 48.6 Newtons approximately.
Learn more about Tension here: brainly.com/question/24994188