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ohaa [14]
3 years ago
6

How will you define motion?

Physics
1 answer:
Naddik [55]3 years ago
3 0
Motion by definition is the movement of things above or below the surface of gravity
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Prof. Kopp is working on an experiment located in an abandoned mine near Duluth, MN. The experiment is located approximately 713
MA_775_DIABLO [31]

Answer:

The average speed of the elevator going down in the abandoned mine is 17.722mph.

Explanation:

If the elevator takes 90 seconds to descend a height of 713m, the average speed of the elevator is:

v_{av}=x_T/t_T=713m/90s=7.922m/s

And if 1m/s is 2.23694mph, the average speed is:

v_{av}=7.922m/s=17.722mph.

8 0
3 years ago
What is a penalty stroke in field hockey?
Paha777 [63]

Answer: D

Explanation: Because the orginal Penalty stroke is Today's field hockey topic is the exciting penalty stroke! What is a stroke? A penalty stroke occurs when an intentional foul happens in the penalty circle (the circle around the goal), the foul prevents a scoring of a opportunity.

4 0
2 years ago
Read 2 more answers
Consider a 30-cm-diameter hemispherical enclosure. The dome is maintained at 600 K, and heat is supplied from the dome at a rate
SIZIF [17.4K]

Answer:

\epsilon_2=0.098

Explanation:

Diameter d=30cm=0.3m

Temperature T=600k

Rate of supply r=65W

Emissivity of base surface \in_b =0.55

Temperature at base T_b=400k

Generally the equation for Area of base surface is mathematically given by

 A_b=\frac{\pi}{4}d^2

 A_b=\frac{\pi}{4}0.3^2

 A_b=0.0707m^2

Generally the equation for Area of Hemispherical dome is mathematically given by

 A_h=\frac{\pi}{2}d^2

 A_h=\frac{\pi}{2}0.3^2

 A_h=0.1414m^2

Since base is a flat surface

 F_{11}+F_{12}=1

 F_{11}=0

Therefore

 F_{12}=1

 A_b=0.0707m^2

Generally the equation for Net rate of radiation heat transfer between two surfaces is mathematically given by

 Q_{21}=-Q_{12}

 Q_{21}=\frac{\sigma(T_1^4-T_2^4)}{\frac{1-\epsilon}{A_b\epsilon_1} +\frac{1}{A_bF_{12}} +\frac{1-\epsilon_2}{A_h*\epsilon_2} }

Where

 \sigma=5.67*10^{-8}

Therefore

  65=\frac{(5.67*10^{-8}(400^4-600^4))}{\frac{1-0.55}{0.0707*0.55}+\frac{1}{0.0707}+\frac{1-\epsilon_2}{0.1414*\epsilon_2}}

 \epsilon_2=0.098

 \epsilon_2 \approx 0.1

Therefore  the emissivity of the dome is

 \epsilon_2=0.098

3 0
2 years ago
What is the fastest the block can be spun at without breaking with the block weighing 10kg and spinning horizontally with a 2m s
larisa86 [58]

The fastest speed before the string breaks is 9.5 m/s

Explanation:

The motion of the block is a uniform circular motion, which is a circular motion with constant speed. The force that keeps the block in circular motion is called centripetal force; its direction is towards the centre of the circle and its magnitude is given by:

F=m\frac{v^2}{r}

where

m is the mass of the block

v is its speed

r is the radius of the circle

In this problem, the centripetal force is provided by the tension in the string, T, so we can write:

T=m\frac{v^2}{r}

The string breaks when the centripetal force becomes larger than the maximum tension in the string:

T_{max}

Re-arranging the equation  for v,

v>\sqrt{\frac{Tr}{m}}

and here we have:

T = 450 N

m = 10 kg

r = 2 m

Substituting,

v>\sqrt{\frac{(450)(2)}{10}}=9.5 m/s

So, the fastest speed before the string breaks is 9.5 m/s.

Learn more about circular motion:

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7 0
3 years ago
when earth and moon are separated by a distance of 3.84×10^8 meters, the magnitude of the gravitational force of attraction betw
sammy [17]

The gravitational force would be 8\cdot 10^{20} N

Explanation:

The magnitude of the gravitational force between two objects is given by

F=G\frac{m_1 m_2}{r^2}

where

G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2} is the gravitational constant

m1, m2 are the masses of the two objects

r is the separation between them

In this case, we can write the gravitational force between the Moon and the Earth as:

F=G\frac{M m}{r^2}

where M is the Earth's mass and m is the Moon's mass.

We know that:

r=3.84\cdot 10^8 m is their separation

F=2.0 \cdot 10^{20}N is the force between them

So we can find:

GMm = Fr^2 = (2.0\cdot 10^{20})(3.84\cdot 10^8)^2=2.95\cdot 10^{37} Nm^2

Now, we are asked to find the gravitational force when the Earth and the Moon are separated by

r'=1.92\cdot 10^8 m

In this case the new force would be

F'=G\frac{M m}{r'^2}

And substituting the values of (GMm) found previously and r', we find

F'=\frac{2.95\cdot 10^{37}}{(1.92\cdot 10^8)^2}=8\cdot 10^{20} N

Learn more about gravitational force:

brainly.com/question/1724648

brainly.com/question/12785992

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6 0
3 years ago
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