Answer:
![4.86\times10^{-7}\ \text{m}](https://tex.z-dn.net/?f=4.86%5Ctimes10%5E%7B-7%7D%5C%20%5Ctext%7Bm%7D)
Explanation:
R = Rydberg constant = ![1.09677583\times 10^7\ \text{m}^{-1}](https://tex.z-dn.net/?f=1.09677583%5Ctimes%2010%5E7%5C%20%5Ctext%7Bm%7D%5E%7B-1%7D)
= Principal quantum number of an energy level = 2
= Principal quantum number of an energy level for the atomic electron transition = 4
Wavelength is given by the Rydberg formula
![\lambda^{-1}=R\left(\dfrac{1}{n_1^2}-\dfrac{1}{n_2^2}\right)\\\Rightarrow \lambda^{-1}=1.09677583\times 10^7\left(\dfrac{1}{2^2}-\dfrac{1}{4^2}\right)\\\Rightarrow \lambda=\left(1.09677583\times 10^7\left(\dfrac{1}{2^2}-\dfrac{1}{4^2}\right)\right)^{-1}\\\Rightarrow \lambda=4.86\times10^{-7}\ \text{m}](https://tex.z-dn.net/?f=%5Clambda%5E%7B-1%7D%3DR%5Cleft%28%5Cdfrac%7B1%7D%7Bn_1%5E2%7D-%5Cdfrac%7B1%7D%7Bn_2%5E2%7D%5Cright%29%5C%5C%5CRightarrow%20%5Clambda%5E%7B-1%7D%3D1.09677583%5Ctimes%2010%5E7%5Cleft%28%5Cdfrac%7B1%7D%7B2%5E2%7D-%5Cdfrac%7B1%7D%7B4%5E2%7D%5Cright%29%5C%5C%5CRightarrow%20%5Clambda%3D%5Cleft%281.09677583%5Ctimes%2010%5E7%5Cleft%28%5Cdfrac%7B1%7D%7B2%5E2%7D-%5Cdfrac%7B1%7D%7B4%5E2%7D%5Cright%29%5Cright%29%5E%7B-1%7D%5C%5C%5CRightarrow%20%5Clambda%3D4.86%5Ctimes10%5E%7B-7%7D%5C%20%5Ctext%7Bm%7D)
The wavelength of the light emitted is
.
Answer: The pressure of the tank will be 2.63 atm
Explanation:
According to ideal gas equation:
![PV=nRT](https://tex.z-dn.net/?f=PV%3DnRT)
P = pressure of gas = ?
V = Volume of gas = 4.44 L
n = number of moles = 0.481
R = gas constant =![0.0821Latm/Kmol](https://tex.z-dn.net/?f=0.0821Latm%2FKmol)
T =temperature =![22.6^0C=(22.6+273)K=295.6K](https://tex.z-dn.net/?f=22.6%5E0C%3D%2822.6%2B273%29K%3D295.6K)
![P=\frac{nRT}{V}](https://tex.z-dn.net/?f=P%3D%5Cfrac%7BnRT%7D%7BV%7D)
![P=\frac{0.481mol\times 0.0821Latm/K mol\times 295.6K}{4.44L}=2.63atm](https://tex.z-dn.net/?f=P%3D%5Cfrac%7B0.481mol%5Ctimes%200.0821Latm%2FK%20mol%5Ctimes%20295.6K%7D%7B4.44L%7D%3D2.63atm)
The pressure of the tank will be 2.63 atm
Answer:
the concentration of bicarbonate is <em>[HCO₃⁻] = 0,03996 M </em>and carbonate is <em>[CO₃²⁻] = 3,56x10⁻⁵ M.</em>
Explanation:
Carbonate-bicarbonate is:
HCO₃⁻ ⇄ CO₃²⁻ + H⁺ With pka = 10,25
Using Henderson-Hasselbalach formula:
pH = pka + log₁₀![\frac{[CO_{3}^{2-}]}{[HCO_{3}^-]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BCO_%7B3%7D%5E%7B2-%7D%5D%7D%7B%5BHCO_%7B3%7D%5E-%5D%7D)
7,2 = 10,25 + log₁₀![\frac{[CO_{3}^{2-}]}{[HCO_{3}^-]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BCO_%7B3%7D%5E%7B2-%7D%5D%7D%7B%5BHCO_%7B3%7D%5E-%5D%7D)
8,91x10⁻⁴ =
<em>(1)</em>
Also:
0,040 M = [CO₃²⁻] + [HCO₃⁻] <em>(2)</em>
Replacing (2) in 1:
<em>[HCO₃⁻] = 0,03996 M</em>
Thus:
<em>[CO₃²⁻] = 3,56x10⁻⁵ M</em>
I hope it helps.
<span>Sedimentary rocks are formed when sediment is deposited out of air, ice, wind, gravity, or water flows carrying the particles in suspension. This sediment is often formed when weathering and erosion break down a rock into loose material in a source area.</span>