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kramer
3 years ago
13

If KL = LM and KJ = JM, find m ∠KJL please, i really need your help!

Mathematics
1 answer:
umka2103 [35]3 years ago
3 0
The triangles are congruent by SAS, so the two angles with 7x and 3x+16 are equal. So

7x=3x+16
4x=16
x=4

So KJL=7(4)=28.
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Which is the solution set of the compound inequality 3.5 x -10> -3 and 8x -9 <39
aivan3 [116]
3.5x-10>-3  add 10 to both sides

3.5x>13  divide both sides by 3.5

x>26/7

x=(26/7, +oo)

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8x-9<39  add 9 to both sides

8x<48  divide both sides by 8

x<6

x=(-oo,6)

Since this is a compound inequality with AND the solution set will be the union of the two intervals found above.

x=(26/7, 6)
7 0
3 years ago
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Is (x + 2) a factor of 3x3 + 4x2 - 4 ?
nordsb [41]

Answer:

No it is not a factor

Step-by-step explanation:

Reason for not being a factor is 3x^3-4x^2-4x. 3x3−4x2−4x 3 x 3 - 4 x 2 - 4 x. Factor x x out of 3x3−4x2−4x 3 x 3 - 4 x 2 - 4 x

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The given series has six terms. what is the sum of the terms of the series? 17 + 25 + 33 + . . . + 57
nikdorinn [45]
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3 0
3 years ago
Marie is bringing bagels and cream cheese to school as a birthday snack for her class. The cost of b bagels and c packages of cr
Julli [10]

Answer:

30.5 is the answer

Step-by-step explanation:

price of 1 bagels=0.85

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30*0.85+2*2.5

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just multiply  with the number of thing by the price of  1 thing

8 0
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Among 500 freshmen pursuing a business degree at a university, 311 are enrolled in an economics course, 243 are enrolled in a ma
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Solution :

Let A = Economics, B = Mathematics

n(A) = 311, n(B) = 243, $n(A \cap B) = 135$

a). So, $n(A \cup B) = n(A) +n(B) - n(A \cap B)$

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b). n(A only) = 311 - 135

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     n(B only) = 243 - 135

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Exactly one of these two courses

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c). Neither economics nor mathematics

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  $=\frac{81}{500}$

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7 0
3 years ago
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