Which temperature change would cause a sample of an ideal gas to double in volume while pressure is held constant? A. From 400K
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Answer:
640.32 g
Explanation:
2KClO₃ → 2KCl + 3O₂
First we <u>convert KClO₃ moles to O₂ moles,</u> using the <em>stoichiometric coefficients</em>:
- 13.34 mol KClO₃ *
= 20.01 mol O₂
Then we <u>convert O₂ moles to grams</u>, using its <em>molar mass</em>:
- 20.01 mol O₂ * 32 g/mol = 640.32 g
So 640.32 g of O₂ are formed from 13.34 moles of KClO₃.