Answer:
![15molH](https://tex.z-dn.net/?f=15molH)
Explanation:
Hello,
In this case, given that one mole of glucose, contains six moles of oxygen (subscript), we can also see it contains twelve moles of hydrogen (subscript), therefore, the moles of hydrogen in the sample are computed by:
![0.75molO*\frac{1molC_6H_{12}O_6}{6molO}*\frac{12molH}{1molC_6H_{12}O_6}\\ \\=1.5molH](https://tex.z-dn.net/?f=0.75molO%2A%5Cfrac%7B1molC_6H_%7B12%7DO_6%7D%7B6molO%7D%2A%5Cfrac%7B12molH%7D%7B1molC_6H_%7B12%7DO_6%7D%5C%5C%20%20%5C%5C%3D1.5molH)
Best regards.
Answer is: <span>because dissolved compounds can crystallizing from solution during filtration and forming crystals on the filter paper or funnel.
</span>Recrystallization<span> is a technique used to purify chemicals by dissolving both impurities and a compound in an appropriate solvent, either compound or impurities can be removed from the solution, leaving the other behind.</span>
The density in lbs/in³ units : 0.697
<h3>Further explanation</h3>
Given
Density of gold is 19.3 g/cm³
Required
Conversion to lbs/in³
Solution
Density is a quantity derived from the mass and volume
Density is the ratio of mass per unit volume
Density formula:
![\large {\boxed {\bold {\rho ~ = ~ \frac {m} {V}}}}](https://tex.z-dn.net/?f=%5Clarge%20%7B%5Cboxed%20%7B%5Cbold%20%7B%5Crho%20~%20%3D%20~%20%5Cfrac%20%7Bm%7D%20%7BV%7D%7D%7D%7D)
Conversion factor
1 g = 0,00220462 lbs
1 cm³ = 0,0610237 in³
So the density :
![\tt 19.3~\dfrac{g}{1~cm^3}\times \dfrac{cm^3}{0.0610237~in^3}\times \dfrac{0.00220462~lbs}{1~g}=0.697~lbs/in^3](https://tex.z-dn.net/?f=%5Ctt%2019.3~%5Cdfrac%7Bg%7D%7B1~cm%5E3%7D%5Ctimes%20%5Cdfrac%7Bcm%5E3%7D%7B0.0610237~in%5E3%7D%5Ctimes%20%5Cdfrac%7B0.00220462~lbs%7D%7B1~g%7D%3D0.697~lbs%2Fin%5E3)
Answer:
They are very reactive, electropositive, monovalent metals forming strongly alkaline hydroxides.
Explanation:
any of the elements lithium, sodium, potassium, rubidium, cesium, and francium, occupying Group IA
Explanation:
The boiling point of petrol is 483K and that of water in 373K. Since the difference between the boiling point temperatures is high, we can use the method of distillation as explained above to obtain petrol and water from the liquid mixture. Therefore, the correct answer is option (A).