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never [62]
2 years ago
14

Would Li CO2 and LiOH produce the same colors? Explain your thinking.

Chemistry
1 answer:
saul85 [17]2 years ago
8 0

Answer:

Lithium hydroxide is a base.

Carbon dioxide is the anhydride of the carbonic acid, H₂CO₃.

Therefore, the reaction awaited is a typical neutralization reaction with the formation of a salt and water.

2LiOH + CO₂ → Li₂CO₃ + H₂O

So, 2*20 = 40 moles of LiOH react with 20 moles of CO₂.

Molar Mass of LiOH = 23.95 g/mol

So, 40 * 23.95 = 958 g

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Explain how you determine molar mass of Ca(No3)2
igor_vitrenko [27]

Answer:

164

1st step we will write desperate molar mass of each element

8 0
3 years ago
What is keq for the reaction 2so2(g) + o2(g) 2so3(g)? apex?
Dennis_Churaev [7]
The  keg for the reaction
2  SO2(g) + O2(g)   →  2  SO3(g)  is

 Keg =  [SO3]^2/ {(SO2)^2 ( O2)}

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7 0
3 years ago
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What monomer is polymerized to make acrylate? What is the chemical name for this popular polymer?
lawyer [7]
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3 0
3 years ago
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Compounds in a and b were named incorrectly. On a sheet of paper draw the molecule that fits the given description. From the str
krok68 [10]

Answer:

a. 4—ethyl—5—methyloctane

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Explanation:Please see attachment for explanation

3 0
3 years ago
500 mL of a solution contains 1000 mg of CaCl2. Molecular weight of CaCl2 is 110 g/mol. Specific gravity of the solution is 0. C
dangina [55]

Answer:

a) 0,2% w/v

b) r=500

c) 0,0182 M

d) 0,0145 m

e) 0,0137 equivalents

Explanation:

a) % w/v means mass of solute in grams per 100 mililiter of solution. Thus:

%w/v= \frac{1,000 g CaCl2}{500mL}×100 = 0,2%w/v

b) Ratio strength is a way to express concentration.  For w/v is in 1g of solute <em>r</em> mililiters of solution have. Thus, r = 500 because we have in the first 1 g of CaCl₂ in 500 mL of solution.

c) Molarity is moles of solute per liter of solution, thus:

1,000 g of CaCl₂ × \frac{1mol}{110g} = 9,09×10⁻³ moles of CaCl₂

500 mL of solution  × \frac{1L}{1000mL} = 0,500 L of solution

M = \frac{9,09x10^{-3} moles }{0,500 L} = 0,0182 M

d) Molality is moles of solute per kg of solution.

Specific gravity is the ratio between density of the solution and density of a reference substance (Usually water). With a specific gravity of 0,8:

kg of solution = 0,500 L of solution × \frac{0,8 kg}{1L} =<em> </em><em>0,625 kg of solution</em>

m = \frac{9,09x10^{-3}moles }{0,625 kg} = 0,0145 m

e)  In a salt, equivalents are the number of moles ables to replace one mole of charge. In CaCl₂ is ¹/₂ because with  ¹/₂ moles of CaCl₂ it is possible to replace 1 mole of charges. Thus, in 1,5 L there are:

1,5 L ×\frac{0,0182 CaCl2 moles}{1L} × \frac{1equivalent}{2 moles} = 0,0137 equivalents

I hope it helps!

7 0
3 years ago
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