Answer:
B.) their electrons are assigned to the s and p orbitals only
Explanation:
Once you get to the fourth row on the periodic table, the transition metals are introduced. The transition metals are located in the d-block and their electrons fill up d orbitals. When an element in the p-block (the right side of the table) is in one of these rows, the d-block has to fill up first.
A controlled experiment is one in which evrerything is held constant except for one verieble, maybe is usually a st of data is taken for a control group.
The relative abundance and the mass number usually they give these to you. They give me both these values in my chemistry class so i just multiply add the products and get my answer
Answer:
The atom is oxidized is Ca.
Explanation:
- The oxidation-reduction reaction contains a reductant and an oxidant (oxidizing agent).
- The oxidation process is the process in which electrons are lost and produce positively charged ions.
- The reduction process is the process in which electrons is gained and negatively charge ions are produced.
- In the reaction of chlorine with calcium:
<em>Ca + Cl₂ → CaCl₂,</em>
Ca loses 2 electrons and is oxidized to Ca²⁺. (Ca <em>→</em> Ca²⁺ + 2e).
Cl is gains 2 electrons in "Cl₂, oxidation state zero" and is reduced to Cl⁻. (Cl₂ + 2e <em>→</em> 2Cl⁻).
Answer:
Explanation:
The solution contain 0.01 M concentration of Ba²⁺
0.01M concentration of Ca²⁺
Ksp ( solubility constant) for BaSO₄ = 1.07 × 10⁻¹⁰
Ksp for CaSO₄ = 7.10 × 10⁻⁵
(BaSO₄) = (Ba²⁺) (SO₄²⁻)
1.07 × 10⁻¹⁰ = 0.01 M (SO₄²⁻)
1.07 × 10⁻¹⁰ / 0.01 = ( SO₄²⁻)
1.07 × 10⁻⁸ M = ( SO₄²⁻)
so the minimum of concentration of concentration sulfate needed is 1.07 × 10⁻⁸ M
For CaSO₄
CaSO₄ = ( Ca²⁺) ( SO₄²⁻)
7.10 × 10⁻⁵ = 0.01 (SO₄²⁻)
(SO₄²⁻) = 7.10 × 10⁻⁵ / 0.01 = 7.10 × 10⁻³ M
so BaSO₄ will precipitate first since its cation (0.01 M Ba²⁺) required a less concentration of SO₄²⁻ (1.07 × 10⁻⁸ M ) compared to CaSO₄
b) The minimum concentration of SO₄²⁻ that will trigger the precipitation of the cation ( 0.01 M Ba²⁺) that precipitates first is 1.07 × 10⁻⁸ M
