Answer:
*If the particles are deflected in opposite directions, it implies that their charges must be opposite
*the force is perpendicular to the speed, therefore it describes a circular movement, one in the clockwise direction and the other in the counterclockwise direction.
Explanation:
When a charged particle enters a magnetic field, it is subjected to a force given by
F = q v x B
where bold letters indicate vectors
this expression can be written in the form of a module
F = qv B sin θ
and the direction of the force is given by the right-hand rule.
In our case the magnetic field is perpendicular to the speed, therefore the angle is 90º and the sin 90 = 1
If the particles are deflected in opposite directions, it implies that their charges must be opposite, one positive and the other negative.
Furthermore, the force is perpendicular to the speed, therefore it describes a circular movement, one in the clockwise direction and the other in the counterclockwise direction.
The difference in the speeds of the two balls when they hit the ground is mathematically given as
V=0.10m/s
<h3>What is the difference in the
speeds of the two balls when they hit the ground.?</h3>
Generally, the equation for Acceleration due to electric field is mathematically given as
For Negative charge
In conclusion, the speed of the negative ball
v1=6.21m/s
The difference in v
V=v1-v2
V=6.31-6.21
V=0.10m/s
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The gravitational potential energy of the rock is:
490 J at 50 m
196 J at 20 m
9.8 J at 1 m
Explanation:
The gravitational potential energy (GPE) of an object is the energy possessed by the object due to its position in the gravitational field.
For an object near the Earth's surface, the GPE is given by
where
m is the mass of the object
is the acceleration of gravity at Earth's surface
h is the heigth of the object relative to the ground
For the rock in this problem,
m = 1 kg
So its GPE at h = 50 m is
The GPE at h = 20 m is
While the GPE at h = 1 m is
Learn more about gravitational potential energy:
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Answer:
Molybdenum and seaborgium