(a) The impulse of the force is 8 N.s
(b) The final velocity of the object if it is initially at 5.33 m/s
(c) The final velocity of the object if it is initially moving along the x - axis with velocity of 22.0 m/s is 3.33 m/s
<h3>What is impulse?</h3>
The change in momentum is equal to the product of impact force applied while colliding and time for that impact.
Impulse = F. Δt = m (Vf -Vi)
where, Vf is the final velocity and Vi is the initial velocity.
Given, the force shown in the force vs. time diagram acts on a 1.5-kg object.
(a) Impulse is given by
Impulse = F. Δt
Put the values, we get
Impulse = 2x3 + 1/2 x2x2
Impulse = 6+2 = 8N.s
Thus, the impulse from the graph is 8 N.s
(b)
Impulse= F. Δt = m (Vf -Vi)
Substitute the values into the expression, we get
8 = 1.5 x (Vf - 0)
Vf = 5.33 m/s
Thus, the final velocity of the object if it is initially at 5.33 m/s
(c)
Impulse= F. Δt = m (Vf -Vi)
Substitute the values into the expression, we get
8 = 1.5 x (Vf +2)
Vf = 3.33 m/s
Thus the final velocity of the object if it is initially moving along the x - axis with velocity of 22.0 m/s is 3.33 m/s.
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