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cestrela7 [59]
3 years ago
10

If some electrons are transferred from object A to object B,

Physics
1 answer:
Igoryamba3 years ago
6 0

Answer: A. Object A will have a positive charge.

Explanation: If the number of protons and electrons are the same, their net charges cancel each other out, and you have a neutral charge. If electrons are transferred to another object, the amount of positive charge will outweigh the amount of negative charge. As a result, you are left with an overall positive charge in object A. Meanwhile, object B is now negative.

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What temperature is required to transfer waste heat to the environment for a heat engine to be 100 percent efficient?
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A cylindrical container with a cross-sectional area of 85.2 cm 2 holds fluid having a density of 806 kg/m 3 . The surface of the
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Help ppls thank u guys <3
Naddik [55]

Answer:

The magnitude of the sum of the two vectors is approximately 169.34 m

Explanation:

The given vectors are;

Vector B;

Magnitude = 101 m

Direction = 60.0°  (30.0° west of north)

Resolving the vector into its x and y component vectors gives;

\underset{B}{\rightarrow} = 101 × cos(60.0°)·i + 101 × sin(60.0°)·j = 55·i + 55·√3·j

∴ \underset{B}{\rightarrow} = 55·i + 55·√3·j

Vector A;

Magnitude = 85.0 m

Direction = West

Resolving the vector into its x and y component vectors gives;

\underset{A}{\rightarrow} = 85.0 × cos(0.0°)·i + 85.0 × sin(0.0°)·j = 85.0·i + 0·j

∴ \underset{A}{\rightarrow} = 85.0·i

The sum of the two vectors is \underset{B}{\rightarrow} + \underset{A}{\rightarrow} = 55·i + 55·√3·j + 85.0·i = 140.0·i + 55·√3·j

The direction of the sum of the two vectors, θ = arctan(y-component of the vector)/(x-component of the vector))

Therefore, θ = arctan((55·√3)/140) ≈ 34.23° north of west or 55.77° west of north

The magnitude of the sum of the two vectors, R is R = √(140² + (55·√3)²) ≈ 169.34 m.

6 0
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