The momentum of the object is 1500 kgm/s.
<h3><u>Explanation:</u></h3>
The law of conservation of momentum states that without effect of any external force in the system, the momentum of the system remains conserved. And momentum is defined as the product of the mass and velocity of the object.
Here, the mass of the 1st body = 200kg.
The mass of the 2nd body = 150kg.
Velocity of the 1st body = 15 m/s.
Velocity of the 2nd body = - 10 m/s.
So, the total momentum of the system before collision = kgm/s
= 1500 kgm/s.
After the collision, the body sticks together.
So, the total mass =200+150 kg = 350 kg.
Momentum remains conserved. So the momentum of the body= 1500 kgm/s.
Answer:
The molar heat of combustion for butanol is 2.7 *10³ kJ/mol
Explanation:
Step 1: Data given
Temperature change = 4.18 °C
mass of butanol = 3.00 grams
When butanol is burned Temperature change = 20.81 °C
Step 2: Calculate Ccalorimeter
Ccal = 21750J / 4.18 °C = 5203.35 J/ °C
Step 3: Calculate heat generated
Heat generated = 20.81 °C * 5203.35 J/°C = 108281.71 J = 108.28 kJ
Step 4: Calculate moles of butanol
Number of moles = mass / molar mass
Number of moles = 3 grams / 74.123 g/mol = 0.04 moles
Step 5: Calculate Molar heat of combustion
Molar heat of combustion = 108.28 kJ / 0.04 moles = 2707 kJ /mol
The molar heat of combustion for butanol is 2.7 *10³ kJ/mol
Answer:
2.44 %
Explanation:
Given that,
The calculated value of specific heat of water to be 4.29 J/g°C
The actual value of the specific heat of water is 4.18J/g°C
We need to find the percentage error of the student
Hence, the student's percent error is 2.44 %.
Answer:The 2nd and 3rd one.
Explanation:
It has the same number of protons but different amount of nuetrons.