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Blizzard [7]
3 years ago
15

Can someone help me please

Physics
2 answers:
algol [13]3 years ago
8 0

Answer:

distance i think im not sure

Sergio039 [100]3 years ago
7 0
The answer to your question is distance
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A joule is equivalent to<br><br> N/s<br> N/m<br> Ndm<br> Nds
skelet666 [1.2K]
A joule is also called a newton metre so it is force in newtons multiplied by distance. Answer 3 seems to fit, assuming dm means “delta m” or a measure of the change of distance in metres.
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4 years ago
Write a brief explanation about how an electric motor works according to what you know about electricity and magnetism. help i d
Lady_Fox [76]
An electric motors works by allowing the flow of electricity to flow throughout the system from the power source to the desired area. The motor is usually used to power other things and/or machines.
5 0
3 years ago
Which statement describes a physical property related to the particles that make up a material? A. Gold ions in a piece of jewel
ohaa [14]

Answer: Metallic bonds between tin ions cause a sheet of tin to be malleable

Explanation:

4 0
3 years ago
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A boy on board a cruise ship drops a 30. 0 gm marble into the ocean. If the resistive force proportionality constant is 0. 500 k
mixer [17]

The terminal speed of the marble is 0.588 m/s.

Given:

We know that,

F = mg                          ......(1)

where,

F = force

m = mass

g = acceleration due to gravity

Also,

v = F/k                            ......(2)

where,

v = terminal speed

k = proportionality constant

Substituting the value of F from equation (1) in equation (2)

v = mg/k                             .......(3)

Given,

m = 30 g = 0.030 kg

k = 0.500 kg/s

g = 9.8 m/s²

To find,

v =?

Put the values in equation (3)

v = mg/k        

v = 0.03(9.8)/ 0.500

= 0.294/0.500

= 0.588 m/s

​

Learn more about the calculation of force, refer to:

brainly.com/question/15562875

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8 0
2 years ago
The dielectric strength of rutile is 6.0 × 106 V/m, which corresponds to the maximum electric field that the dielectric can sust
VLD [36.1K]

Answer:

6.48*10⁻⁷ C

Explanation:

  • By definition, the capacitance of a capacitor is expressed as follows:

       C =\frac{Q}{V}

  • where Q is the charge on one of the plates of the capacitor, and V the potential difference between the plates.
  • The maximum electric field, the potential difference, and the distance between plates are related by the following expression:

        V = E_{max} * d

  • Replacing by the givens, we can find V as follows:

        V = 6.0e6 V/m * 0.00108 m= 6480 V

  • Now, we can find the maximum charge Qmax,  as follows:

        Q_{max} = C*V = 1e-10F* 6480 V = 6.48e-7 C

  • The maximum charge that the capacitor can hold is 6.48*10⁻⁷ C.
5 0
3 years ago
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