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Hoochie [10]
3 years ago
11

The 1995 Nobel Prize in Chemistry was shared by Paul Crutzen, F. Sherwood Rowland, and Mario Molina for their work concerning th

e formation and decomposition of ozone in the stratosphere. Rowland and Molina hypothesized that chlorofluorocarbons (CFCs) in the stratosphere break down upon exposure to UV radiation, producing chlorine atoms. Chlorine was previously identified as a catalyst in the breakdown of ozone into oxygen gas. Using the enthalpy of reaction for two reactions with ozone, determine the enthalpy of reaction for the reaction of chlorine with ozone. 1) ClO (g) + O3 (gO -----> Cl (g) + 2O2 (g) ?H rxn = -122.8 kJ 2) 2O3 (g) ------> 3O2 (g) ?Hrxn= -285.3 kJ 3) O3(g) + Cl (g) ---------> ClO(g) + O2 (g) ?Hrxn = ? Find the missing ?Hrxn for reaction
Chemistry
1 answer:
Kaylis [27]3 years ago
5 0

Answer:

The enthalpy of reaction when chlorine reacts with ozone is -162.5 kJ/mol.

Explanation:

ClO (g) + O_3 (g)\rightarrow Cl (g) + 2O_2 (g) ,\Delta H_{rxn,1}= -122.8 kJ/mol..[1]

2O_3 (g) \rightarrow 3O_2 (g) \Delta H_{rxn,2}= -285.3 kJ/mol..[2]

O_3(g) + Cl (g)\rightarrow ClO(g) + O_2 (g) \Delta H_{rxn,3} = ?...[3]

Applying Hess's law:

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

[2] - [1]  = [3]

\Delta H_{rxn,3} =\Delta H_{rxn,2} -\Delta H_{rxn,1}

=-285.3 kJ/mol-(-122.8 kJ/mol)=-162.5 kJ/mol

The enthalpy of reaction when chlorine reacts with ozone is -162.5 kJ/mol.

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If we assume that there will be enough Hydrogen for the reaction to occur, then there will be 8 moles of NH

Explanation:

The balanced equation will look like this:

4N2 + 4H2 -> 8NH

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Which of the following observations indicates that an atom has neutrons?
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When the alpha particle hits the beryllium atoms at high speeds, it splits the atomic nuclei hence causing the nuclei particles flying. When exposed to an electric field, the path of the proton is curved towards the negative pole while neutrons are unaffected.  

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2 years ago
How many moles are in 12 liters of Cl2?
RoseWind [281]

Answer:

\boxed {\boxed {\sf 0.54 \ mol \ Cl_2}}

Explanation:

A mole is any quantity of a substance that contains 6.02 × 10²³ particles. At standard temperature and pressure, or STP, 1 mole of as is equal to 22.4 liters. This is true for any gas, regardless of the specific kind.

Although it is not specified, we can assume this gas is at STP. Let's set up a ratio using this information: 22.4 L/mol

\frac {22.4 \ L \ Cl_2}{1 \ mol \ Cl_2}

Multiply by the given number of liters: 12

12 \ L \ Cl_2 *\frac {22.4 \ L \ Cl_2}{1 \ mol \ Cl_2}

Flip the ratio so the liters of chlorine cancel.

12 \ L \ Cl_2 * \frac {1 \ mol \ Cl_2}{22.4 \ L \ Cl_2}

12  * \frac {1 \ mol \ Cl_2}{22.4 }

\frac {12}{22.4 }  \ mol \ Cl_2

0.53571428571 \ mol \ Cl_2

The original measurement of liters has 2 significant figures, so our answer must have the same.

For the number we found, that is the hundredth place.

  • 0.53<u>5</u>71428571

The 5 in the thousandth place tells us to round the 3 up to a 4.

0.54 \ mol \ Cl_2

12 liters of chlorine gas at STP is approximately <u>0.54 moles of chlorine gas.</u>

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