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Hoochie [10]
3 years ago
11

The 1995 Nobel Prize in Chemistry was shared by Paul Crutzen, F. Sherwood Rowland, and Mario Molina for their work concerning th

e formation and decomposition of ozone in the stratosphere. Rowland and Molina hypothesized that chlorofluorocarbons (CFCs) in the stratosphere break down upon exposure to UV radiation, producing chlorine atoms. Chlorine was previously identified as a catalyst in the breakdown of ozone into oxygen gas. Using the enthalpy of reaction for two reactions with ozone, determine the enthalpy of reaction for the reaction of chlorine with ozone. 1) ClO (g) + O3 (gO -----> Cl (g) + 2O2 (g) ?H rxn = -122.8 kJ 2) 2O3 (g) ------> 3O2 (g) ?Hrxn= -285.3 kJ 3) O3(g) + Cl (g) ---------> ClO(g) + O2 (g) ?Hrxn = ? Find the missing ?Hrxn for reaction
Chemistry
1 answer:
Kaylis [27]3 years ago
5 0

Answer:

The enthalpy of reaction when chlorine reacts with ozone is -162.5 kJ/mol.

Explanation:

ClO (g) + O_3 (g)\rightarrow Cl (g) + 2O_2 (g) ,\Delta H_{rxn,1}= -122.8 kJ/mol..[1]

2O_3 (g) \rightarrow 3O_2 (g) \Delta H_{rxn,2}= -285.3 kJ/mol..[2]

O_3(g) + Cl (g)\rightarrow ClO(g) + O_2 (g) \Delta H_{rxn,3} = ?...[3]

Applying Hess's law:

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

[2] - [1]  = [3]

\Delta H_{rxn,3} =\Delta H_{rxn,2} -\Delta H_{rxn,1}

=-285.3 kJ/mol-(-122.8 kJ/mol)=-162.5 kJ/mol

The enthalpy of reaction when chlorine reacts with ozone is -162.5 kJ/mol.

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Using the balanced equation below, how many moles of water can be produced when 4 grams of Hydrogen react? 2H2(g)+O2(g) —> 2H
gavmur [86]

Answer:

4 × 10 g

Explanation:

Step 1: Write the balanced equation

2 H₂(g) + O₂(g) ⇒ 2 H₂O(I)

Step 2: Calculate the moles corresponding to 4 g of H₂

The molar mass of H₂ is 2.02 g/mol.

4 g × 1 mol/2.02 g = 2 mol

Step 3: Calculate the moles of H₂O produced from 2 moles of H₂

The molar ratio of H₂ to H₂O is 2:2. The moles of H₂O produced are 2/2 × 2 mol = 2 mol.

Step 4: Calculate the mass corresponding to 2 moles of H₂O

The molar mass of H₂O is 18.02 g/mol.

2 mol × 18.02 g/mol = 4 × 10 g

7 0
3 years ago
Heelp
Alchen [17]
Balanced:
1. <span>Na2O + H2O ---> 2NaOH
2. </span><span>K2O + H2O ---> 2KOH
3. </span><span>MgO + H2O ---> Mg(OH)2
4. </span><span>CaO + H2O ---> Ca(OH)2
5. </span><span>SO2 + H2O ⇄ H2SO3
6. </span>SO3 + H2O ---> H2SO4
All except by 2 were balanced.
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3 years ago
An aqueous solution has 124 g of a salt dissolved in 1000 g of solution. What is the concentration of the salt in units of %?​
tester [92]

Answer: 12.4%

Explanation:

124/1000 * 100 = 12.4%

3 0
2 years ago
Calculate the vapor pressure at 35ºC of a solution made by dissolving 20.2 g of sucrose (C12H22O11)in 60.5 g of water. The vapor
sukhopar [10]

Answer:

P' = 41.4 mmHg → Vapor pressure of solution

Explanation:

ΔP = P° . Xm

ΔP = Vapor pressure of pure solvent (P°) - Vapor pressure of solution (P')

Xm = Mole fraction for solute (Moles of solvent /Total moles)

Firstly we determine the mole fraction of solute.

Moles of solute → Mass . 1 mol / molar mass

20.2 g . 1 mol / 342 g = 0.0590 mol

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Total moles = 3.36 mol + 0.0590 mol = 3.419 moles

Xm = 0.0590 mol / 3.419 moles → 0.0172

Let's replace the data in the formula

42.2 mmHg - P' = 42.2 mmHg . 0.0172

P' = - (42.2 mmHg . 0.0172 - 42.2 mmHg)

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3 years ago
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mojhsa [17]

in the image there is answer okk

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